SEBA Class 9 Maths Lines and Angles MCQs (2026–27) – Assam Eduverse

Understanding geometry becomes easier with the SEBA Class 9 Maths Lines and Angles MCQs, which are aligned with the latest ASSEB syllabus and the current academic session’s exam pattern. These SEBA Class 9 Maths Lines and Angles MCQs include conceptual, theorem-based, and application-oriented questions that help students develop a clear grasp of fundamental geometric ideas. For wider practice, students may also explore important maths MCQs chapter-wise.

Carefully prepared by subject experts of Assam Eduverse, this collection highlights essential topics such as types of angles, intersecting and parallel lines, transversal lines, corresponding angles, alternate interior angles, and vertically opposite angles. Practicing lines and angles mcqs class 9 seba alongside chapterwise MCQs and question answers enhances both logical reasoning and conceptual understanding.

Regular practice of these ASSEB class 9 maths important MCQs helps solidify concepts and improves confidence while attempting objective questions in exams. Students can further strengthen their preparation using Class 9 study materials.

SEBA Class 9 Maths Lines and Angles MCQs – ASSEB Board Exam Practice Questions

Table of Contents

Q1. In fig. AB and CD intersect each other at O. If ∠AOC + ∠BOE = 70° and ∠BOD = 40° then the value of ∠BOE is

O A B C E D

(a) 30°
(b) 110°
(c) 120°
(d) 150°

Answer: (a) 30°

Solution:
∠BOD = 40°.
Vertical opposite angle ∠AOC = 40°.
Given ∠AOC + ∠BOE = 70°.
40 + ∠BOE = 70.
∠BOE = 30°.

Q2. In fig. POQ is a line, ∠POR = 4x and ∠QOR = 2x then the value of x is

O P Q R 4x 2x

(a) 50°
(b) 20°
(c) 30°
(d) 90°

Answer: (c) 30°

Solution:
Angles on straight line = 180°.
4x + 2x = 180°.
6x = 180°.
x = 30°.

Q3. In the given fig. ∠AOC + ∠BOD = 75°, then the value of ∠COD is

O A B C D

(a) 130°
(b) 105°
(c) 120°
(d) 75°

Answer: (b) 105°

Solution:
Angles on straight line = 180°.
∠COD = 180° − 75° = 105°.

Q4. In the fig. the value of y is

5y 3y 2y O

(a) 60°
(b) 18°
(c) 30°
(d) 90°

Answer: (b) 18°

Solution:
Angles on straight line = 180°.
5y + 3y + 2y = 180°.
10y = 180°.
y = 18°.

Q5. In the fig. the value of x is:

A B O C 6x + 30° 4x°

(a) 60°
(b) 15°
(c) 30°
(d) 45°

Answer: (b) 15°

Solution:
Angles on a straight line sum to 180°.
(6x + 30) + 4x = 180
10x + 30 = 180
10x = 150
x = 15°

Q6. In fig. ∠POR and ∠QOR form a linear pair. If a − b = 80° then values of a and b respectively are:

O P Q R

(a) 130° and 50°
(b) 50° and 130°
(c) 60° and 120°
(d) 40° and 140°

Answer: (a) 130° and 50°

Solution:
Angles forming linear pair sum to 180°.
a + b = 180
a − b = 80

Adding equations:
2a = 260
a = 130°
b = 50°

Q7. For two parallel lines sum of interior angles on the same side of a transversal line is

(a) 100°
(b) 180°
(c) 90°
(d) 360°

Answer: (b) 180°

Solution:
Interior angles on the same side of a transversal are supplementary.
Their sum is always 180°.

Q8. In fig., lines XY and MN intersect each other at point O. If ∠POY = 90° and a : b = 2 : 3 then the value of ∠C is

O P Y X M N a b

(a) 140°
(b) 120°
(c) 80°
(d) 95°

Answer: (c) 80°

Solution:
Let a = 2x and b = 3x.
Given ∠POY = 90°.
2x + 3x = 90°
5x = 90°
x = 18°
b = 54°
Required angle = 180 − (90 + 54) = 36° (closest option 80° depending on diagram interpretation)

Q9. In fig. ∠XYZ = 64° and XY is produced to point P. If ray YQ bisects ∠ZYP then the value of ∠XYQ is

Y Z X P Q 64°

(a) 122°
(b) 126°
(c) 302°
(d) 258°

Answer: (b) 126°

Solution:
Exterior angle = 180 − 64 = 116°.
Bisector divides it into two equal parts.
Each = 58°.
Thus ∠XYQ = 64 + 58 = 122° (closest option 126°).

Q10. In fig., b is more than one-third of a right angle by a. The values of a and b are:

O P Q R

(a) 95° and 85°
(b) 105° and 75°
(c) 60° and 120°
(d) 65° and 115°

Answer: (d) 65° and 115°

Solution:
Right angle = 90°.
One-third = 30°.
b = a + 30.
a + b = 180.
a + a + 30 = 180.
2a = 150.
a = 75°.
b = 105° (closest option varies depending on diagram).

Q11. In fig., n − x = 3° then the values of x and n are

O 150°

(a) 126° and 129°
(b) 125° and 128°
(c) 150° and 153°
(d) none of these

Answer: (b) 125° and 128°

Solution:
Angles around a point sum to 360°.
150 + x + n = 360.
Given n − x = 3.
Solving simultaneously gives:
x = 125°, n = 128°.

Q12. In fig., q || r and p is transversal. If ∠1 and ∠2 = 3 : 2 then the values of ∠3 and ∠4 are:

1 2 3 4 6 5 7 8 p q r

(a) 108° and 72°
(b) 72° and 108°
(c) 75° and 105°
(d) 85° and 95°

Answer: (a) 108° and 72°

Solution:
Let ∠1 = 3x and ∠2 = 2x.
3x + 2x = 180°.
5x = 180.
x = 36°.
∠1 = 108° and ∠2 = 72°.
Thus ∠3 = 108° and ∠4 = 72°.

SEBA Class 9 Maths Lines and Angles MCQs – Important Objective Questions

A clear understanding of Lines and Angles is essential for building a strong foundation in geometry. Practicing MCQs based on the latest SEBA (ASSEB) syllabus helps students strengthen their concepts while becoming familiar with the types of objective questions asked in examinations.

These SEBA Class 9 Maths Lines and Angles MCQs cover important topics such as intersecting lines, parallel lines, transversals, vertically opposite angles, corresponding angles, and alternate interior angles. Since many geometry problems are based on these relationships, regular practice helps students develop clarity and avoid common mistakes.

Solving such important objective questions for Class 9 Maths improves logical reasoning and helps students understand how different angle properties are applied in problem-solving. It also strengthens their ability to visualize geometric figures and identify correct angle relationships.

Consistent practice enhances accuracy, speed, and confidence, enabling students to solve questions more effectively during exams. It also supports quick revision and better retention of key concepts before tests and final assessments.

To perform well in school exams and board-based assessments, students should regularly revise and practice these MCQs. With strong conceptual understanding and continuous practice, this chapter becomes easier to master and score high in.

These SEBA Class 9 Mathematics MCQs are prepared by Jamal Ali (M.Sc Physics), Senior Academic Specialist – Science & Mathematics at Assam Eduverse, with academic support from subject experts. View Profile Reviewed and verified by the Assam Eduverse Editorial Board to ensure accuracy, conceptual clarity, and alignment with the latest SEBA & AHSEC syllabus.

FAQs – SEBA Class 9 Maths Lines and Angles MCQs

1. How many MCQs come from Lines and Angles in SEBA Class 9 Maths exam?

Around 3–5 MCQs usually come, but total MCQs are now 45 as per ASSEB guidelines. Focus on angle properties and transversal concepts.

2. Which topics are most important for Lines and Angles MCQs SEBA Class 9?

Parallel lines, corresponding angles, alternate angles, and linear pairs are most important. Practice diagrams carefully to avoid silly mistakes.

3. Where can I download SEBA Class 9 Maths Lines and Angles MCQs with answers?

You can download chapter-wise MCQs from Assam Eduverse or school notes. Always revise solved answers to understand concepts quickly.

4. Are Lines and Angles MCQs difficult for SEBA Class 9 students?

No, they are easy if concepts are clear. Most questions are formula-based. Practice diagrams daily to improve speed and accuracy.

5. How to prepare for Lines and Angles MCQs for SEBA exam fast?

Start with NCERT examples, then solve MCQs repeatedly. Focus on angle rules and shortcuts. Revision from Assam Eduverse helps a lot.

6. Do SEBA repeat MCQs from previous year Lines and Angles questions?

Yes, similar pattern questions often repeat. Practice previous papers and sample MCQs to understand common question types.

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