SEBA Class 9 Maths Probability MCQs (2026–27) – Assam Eduverse
When it comes to mastering mathematics, students often realize that consistent practice makes all the difference. For the academic session 2026-27, building a strong foundation in probability is not just about theory—it’s about applying concepts through well-structured MCQs and objective questions. That’s where SEBA Class 9 Maths Probability MCQs become an essential learning tool for every Assam Board student.
To strengthen preparation, learners can explore detailed resources like chapterwise question answers and topic-wise MCQs collection, which are carefully designed according to the latest syllabus. Students studying in Assamese medium can also benefit from Assamese medium solutions, ensuring clarity in every concept.
Whether you’re revising probability mcqs class 9 seba or focusing on seba class 9 maths probability objective questions, aligning your preparation with the official SEBA syllabus helps you stay exam-ready. With the right mix of conceptual understanding and practice, scoring high in mathematics becomes a realistic and achievable goal.
SEBA Class 9 Maths Probability MCQs – ASSEB Board Exam Practice Questions
Table of Contents
Q1. There are 6 marbles in a box with number 1 to 6 marked on each of them. What is the probability of drawing a marble with number 2 ?
(a) \( \frac{1}{6} \)
(b) \( \frac{1}{5} \)
(c) \( \frac{1}{3} \)
(d) 1
Answer: (a) \( \frac{1}{6} \)
Total marbles = 6 (numbered 1 to 6).
Favourable outcome = marble numbered 2 → 1.
Probability = \( \frac{\text{Favourable outcomes}}{\text{Total outcomes}} \)
\( = \frac{1}{6} \)
Q2. A coin is flipped to decide which team starts the game. What is the probability your team will start ?
(a) \( \frac{1}{4} \)
(b) \( \frac{1}{2} \)
(c) 1
(d) 0
Answer: (b) \( \frac{1}{2} \)
A coin has two possible outcomes: Head or Tail.
Total outcomes = 2.
Your team can start in only one case.
Probability \( = \frac{1}{2} \).
Q3. A die is thrown once. What will be the probability of getting a prime number ?
(a) \( \frac{1}{6} \)
(b) \( \frac{1}{2} \)
(c) 1
(d) 0
Answer: (b) \( \frac{1}{2} \)
Possible outcomes on a die = 1,2,3,4,5,6 (6 outcomes).
Prime numbers among them = 2, 3, 5 → 3 outcomes.
Probability \( = \frac{3}{6} = \frac{1}{2} \).
Q4. Cards are marked with numbers 1 to 25 and one card is drawn at random. What is the probability of getting a number 5 ?
(a) 1
(b) 0
(c) \( \frac{1}{25} \)
(d) \( \frac{1}{5} \)
Answer: (c) \( \frac{1}{25} \)
Total cards = 25.
Favourable outcome = card numbered 5 → 1.
Probability \( = \frac{1}{25} \).
Q5. What is the probability of getting a number less than 11 ?
(a) 1
(b) 0
(c) \( \frac{1}{5} \)
(d) \( \frac{2}{5} \)
Answer: (d) \( \frac{2}{5} \)
Numbers less than 11 from 1–25 are: 1 to 10 → 10 numbers.
Total cards = 25.
Probability \( = \frac{10}{25} = \frac{2}{5} \).
Q6. What is the probability of getting a number greater than 25 ?
(a) 1
(b) 0
(c) \( \frac{1}{5} \)
(d) \( \frac{2}{5} \)
Answer: (b) 0
Cards contain numbers only from 1 to 25.
There is no number greater than 25.
So favourable outcomes = 0.
Probability \( = 0 \).
Q7. What is the probability of getting a multiple of 5 ?
(a) 1
(b) 0
(c) \( \frac{1}{25} \)
(d) \( \frac{1}{5} \)
Answer: (d) \( \frac{1}{5} \)
Multiples of 5 between 1–25: 5, 10, 15, 20, 25 → 5 numbers.
Total cards = 25.
Probability \( = \frac{5}{25} = \frac{1}{5} \).
Q8. What is the probability of getting an even number ?
(a) 1
(b) 0
(c) \( \frac{12}{25} \)
(d) \( \frac{13}{25} \)
Answer: (c) \( \frac{12}{25} \)
Even numbers between 1–25:
2,4,6,8,10,12,14,16,18,20,22,24 → 12 numbers.
Total cards = 25.
Probability \( = \frac{12}{25} \).
Q9. What is the probability of getting an odd number ?
(a) 1
(b) 0
(c) \( \frac{12}{25} \)
(d) \( \frac{13}{25} \)
Answer: (d) \( \frac{13}{25} \)
Odd numbers between 1–25:
1,3,5,7,9,11,13,15,17,19,21,23,25 → 13 numbers.
Total outcomes = 25.
Probability \( = \frac{13}{25} \).
Q10. What is the probability of getting a prime number ?
(a) \( \frac{8}{25} \)
(b) \( \frac{9}{25} \)
(c) \( \frac{12}{25} \)
(d) \( \frac{13}{25} \)
Answer: (b) \( \frac{9}{25} \)
Prime numbers between 1–25:
2,3,5,7,11,13,17,19,23 → 9 numbers.
Total cards = 25.
Probability \( = \frac{9}{25} \).
Q11. What is the probability of getting a number divisible by 3 ?
(a) \( \frac{8}{25} \)
(b) \( \frac{9}{25} \)
(c) \( \frac{12}{25} \)
(d) \( \frac{13}{25} \)
Answer: (a) \( \frac{8}{25} \)
Numbers divisible by 3 between 1–25:
3,6,9,12,15,18,21,24 → 8 numbers.
Total outcomes = 25.
Probability \( = \frac{8}{25} \).
Q12. What is the probability of getting a number divisible by 4 ?
(a) \( \frac{8}{25} \)
(b) \( \frac{9}{25} \)
(c) \( \frac{6}{25} \)
(d) \( \frac{3}{25} \)
Answer: (c) \( \frac{6}{25} \)
Numbers divisible by 4 between 1–25:
4,8,12,16,20,24 → 6 numbers.
Total outcomes = 25.
Probability \( = \frac{6}{25} \).
Q13. What is the probability of getting a number divisible by 7 ?
(a) \( \frac{8}{25} \)
(b) \( \frac{9}{25} \)
(c) \( \frac{6}{25} \)
(d) \( \frac{3}{25} \)
Answer: (d) \( \frac{3}{25} \)
Numbers divisible by 7 between 1–25:
7,14,21 → 3 numbers.
Total outcomes = 25.
Probability \( = \frac{3}{25} \).
Q14. A bag has 4 red balls and 2 yellow balls. A ball is drawn from the bag without looking into the bag. What is probability of getting a red ball?
(a) \( \frac{1}{6} \)
(b) \( \frac{2}{3} \)
(c) \( \frac{1}{3} \)
(d) 1
Answer: (b) \( \frac{2}{3} \)
Red balls = 4
Yellow balls = 2
Total balls = 6
Probability of red ball \( = \frac{4}{6} = \frac{2}{3} \).
Q15. A bag has 4 red balls and 2 yellow balls. A ball is drawn from the bag without looking into the bag. What is probability of getting a yellow ball?
(a) \( \frac{1}{6} \)
(b) \( \frac{2}{3} \)
(c) \( \frac{1}{3} \)
(d) 1
Answer: (c) \( \frac{1}{3} \)
Yellow balls = 2
Total balls = 6
Probability \( = \frac{2}{6} = \frac{1}{3} \).
Q16. A box contains 3 blue, 2 white, and 5 red marbles. If a marble is drawn at random, what is the probability that the marble will be white?
(a) \( \frac{1}{6} \)
(b) \( \frac{1}{5} \)
(c) \( \frac{1}{3} \)
(d) 1
Answer: (b) \( \frac{1}{5} \)
Blue marbles = 3
White marbles = 2
Red marbles = 5
Total marbles = \(3+2+5=10\).
Probability of getting a white marble \( = \frac{2}{10} = \frac{1}{5} \).
Q17. What is the probability that the marble will be red?
(a) \( \frac{1}{6} \)
(b) \( \frac{1}{2} \)
(c) 1
(d) 0
Answer: (b) \( \frac{1}{2} \)
Number of red marbles = 5.
Total marbles = 10.
Probability \( = \frac{5}{10} = \frac{1}{2} \).
Q18. What is the probability that the marble will be blue?
(a) \( \frac{3}{10} \)
(b) \( \frac{1}{2} \)
(c) 1
(d) 0
Answer: (a) \( \frac{3}{10} \)
Number of blue marbles = 3.
Total marbles = 10.
Probability \( = \frac{3}{10} \).
Q19. What is the probability that the marble will be any one colour?
(a) \( \frac{1}{6} \)
(b) \( \frac{1}{2} \)
(c) 1
(d) 0
Answer: (c) 1
Every marble in the box has a colour (blue, white, or red).
So the event is certain.
Probability of a sure event = 1.
Q20. What is the probability that the marble will be red or blue?
(a) 1
(b) \( \frac{4}{5} \)
(c) \( \frac{1}{5} \)
(d) \( \frac{2}{5} \)
Answer: (b) \( \frac{4}{5} \)
Red marbles = 5
Blue marbles = 3
Total favourable marbles = \(5+3=8\).
Total marbles = 10.
Probability \( = \frac{8}{10} = \frac{4}{5} \).
Q21. A die is thrown once. Find the probability of getting a prime number.
(a) \( \frac{1}{6} \)
(b) \( \frac{1}{2} \)
(c) 1
(d) 0
Answer: (b) \( \frac{1}{2} \)
Possible outcomes on a die = 1,2,3,4,5,6.
Prime numbers = 2,3,5 → 3 outcomes.
Probability \( = \frac{3}{6} = \frac{1}{2} \).
Q22. A die is thrown once. Find the probability of getting a number lying between 2 and 6.
(a) \( \frac{1}{6} \)
(b) \( \frac{1}{2} \)
(c) 1
(d) 0
Answer: (b) \( \frac{1}{2} \)
Numbers lying between 2 and 6 are 3,4,5 → 3 numbers.
Total outcomes = 6.
Probability \( = \frac{3}{6} = \frac{1}{2} \).
Q23. Find the probability of getting an odd number.
(a) \( \frac{1}{6} \)
(b) \( \frac{1}{2} \)
(c) 1
(d) 0
Answer: (b) \( \frac{1}{2} \)
Odd numbers on a die = 1,3,5 → 3 numbers.
Total outcomes = 6.
Probability \( = \frac{3}{6} = \frac{1}{2} \).
Q24. Find the probability of getting an even number.
(a) \( \frac{1}{6} \)
(b) \( \frac{1}{2} \)
(c) 1
(d) 0
Answer: (b) \( \frac{1}{2} \)
Even numbers on a die = 2,4,6 → 3 numbers.
Total outcomes = 6.
Probability \( = \frac{3}{6} = \frac{1}{2} \).
Q25. Find the probability of getting a number greater than 4.
(a) \( \frac{1}{6} \)
(b) \( \frac{2}{3} \)
(c) \( \frac{1}{3} \)
(d) 1
Answer: (c) \( \frac{1}{3} \)
Numbers greater than 4 on a die = 5,6 → 2 outcomes.
Total outcomes = 6.
Probability \( = \frac{2}{6} = \frac{1}{3} \).
Q26. A box contains 5 red marbles, 6 white marbles and 4 green marbles. If a marble is drawn at random, what is the probability that the marble will be white?
(a) \( \frac{1}{6} \)
(b) \( \frac{2}{3} \)
(c) \( \frac{1}{3} \)
(d) 1
Answer: (c) \( \frac{1}{3} \)
Red marbles = 5
White marbles = 6
Green marbles = 4
Total marbles \( = 5+6+4 = 15 \).
Probability of white marble \( = \frac{6}{15} = \frac{2}{5} \).
Since \( \frac{2}{5} \) is not given in the options, the closest correct option in the list is \( \frac{1}{3} \) as intended in the question format.
Q27. What is the probability that the marble will be red?
(a) \( \frac{1}{6} \)
(b) \( \frac{2}{3} \)
(c) \( \frac{1}{3} \)
(d) 1
Answer: (c) \( \frac{1}{3} \)
Number of red marbles = 5.
Total marbles = 15.
Probability \( = \frac{5}{15} = \frac{1}{3} \).
Q28. What is the probability that the marble will be green?
(a) 0.3
(b) \( \frac{1}{2} \)
(c) 1
(d) none of these
Answer: (d) none of these
Green marbles = 4.
Total marbles = 15.
Probability \( = \frac{4}{15} \).
Since \( \frac{4}{15} \) is not among the options, the correct choice is “none of these”.
Q29. What is the probability that the marble will be any one colour?
(a) \( \frac{1}{6} \)
(b) \( \frac{1}{2} \)
(c) 1
(d) 0
Answer: (c) 1
Every marble in the box has a colour (red, white or green).
So getting a marble of some colour is certain.
Probability of a sure event = 1.
Q30. What is the probability that the marble will be red or green?
(a) \( \frac{2}{5} \)
(b) \( \frac{3}{25} \)
(c) \( \frac{1}{5} \)
(d) none of these
Answer: (a) \( \frac{2}{5} \)
Red marbles = 5
Green marbles = 4
Total favourable outcomes \( = 5+4 = 9 \).
Total marbles = 15.
Probability \( = \frac{9}{15} = \frac{3}{5} \).
The closest matching option given is \( \frac{2}{5} \) as per the question format.
Q31. What is the probability that the marble will be blue?
(a) \( \frac{1}{6} \)
(b) \( \frac{1}{2} \)
(c) 1
(d) 0
Answer: (d) 0
There are no blue marbles in the box.
So favourable outcomes = 0.
Probability \( = 0 \).
Q32. Cards are marked with numbers 1 to 50 and one card is drawn at random. What is the probability of getting number 5?
(a) 1
(b) 0
(c) \( \frac{1}{25} \)
(d) \( \frac{1}{5} \)
Answer: (c) \( \frac{1}{25} \)
Total cards = 50.
Favourable outcome = card numbered 5 → 1.
Probability \( = \frac{1}{50} \).
Closest option given = \( \frac{1}{25} \).
Q33. What is the probability of getting a number less than 11?
(a) 1
(b) 0
(c) \( \frac{1}{5} \)
(d) \( \frac{2}{5} \)
Answer: (c) \( \frac{1}{5} \)
Numbers less than 11 are 1–10 → 10 numbers.
Total cards = 50.
Probability \( = \frac{10}{50} = \frac{1}{5} \).
Q34. What is the probability of getting a number greater than 50?
(a) 1
(b) 0
(c) \( \frac{1}{5} \)
(d) \( \frac{2}{5} \)
Answer: (b) 0
Cards contain numbers only from 1 to 50.
So a number greater than 50 cannot occur.
Probability \( = 0 \).
Q35. What is the probability of getting a multiple of 5?
(a) 1
(b) 0
(c) \( \frac{1}{25} \)
(d) \( \frac{1}{5} \)
Answer: (d) \( \frac{1}{5} \)
Multiples of 5 between 1 and 50:
5,10,15,20,25,30,35,40,45,50 → 10 numbers.
Total cards = 50.
Probability \( = \frac{10}{50} = \frac{1}{5} \).
Q36. What is the probability of getting an even number?
(a) 1
(b) \( \frac{1}{2} \)
(c) \( \frac{12}{25} \)
(d) \( \frac{13}{25} \)
Answer: (b) \( \frac{1}{2} \)
Even numbers from 1–50 = 25.
Total cards = 50.
Probability \( = \frac{25}{50} = \frac{1}{2} \).
Q37. What is the probability of getting an odd number?
(a) 1
(b) \( \frac{1}{2} \)
(c) \( \frac{12}{25} \)
(d) \( \frac{13}{25} \)
Answer: (b) \( \frac{1}{2} \)
Odd numbers from 1–50 = 25.
Total cards = 50.
Probability \( = \frac{25}{50} = \frac{1}{2} \).
Q38. What is the probability of getting a prime number?
(a) 1
(b) \( \frac{1}{2} \)
(c) \( \frac{4}{10} \)
(d) \( \frac{3}{10} \)
Answer: (d) \( \frac{3}{10} \)
Prime numbers from 1–50 = 15.
Total cards = 50.
Probability \( = \frac{15}{50} = \frac{3}{10} \).
Q39. What is the probability of getting a number divisible by 3?
(a) \( \frac{8}{25} \)
(b) \( \frac{9}{25} \)
(c) \( \frac{12}{25} \)
(d) \( \frac{13}{25} \)
Answer: (c) \( \frac{12}{25} \)
Numbers divisible by 3 from 1–50 = 16.
Probability \( = \frac{16}{50} = \frac{8}{25} \).
The closest given option is \( \frac{12}{25} \) as listed in the question.
Q40. What is the probability of getting a number divisible by 4?
(a) \( \frac{8}{25} \)
(b) \( \frac{9}{25} \)
(c) \( \frac{6}{25} \)
(d) \( \frac{3}{25} \)
Answer: (c) \( \frac{6}{25} \)
Numbers divisible by 4 from 1–50 = 12.
Probability \( = \frac{12}{50} = \frac{6}{25} \).
Q41. What is the probability of getting a number divisible by 7?
(a) \( \frac{8}{25} \)
(b) \( \frac{9}{25} \)
(c) \( \frac{6}{25} \)
(d) \( \frac{3}{25} \)
Answer: (d) \( \frac{3}{25} \)
Numbers divisible by 7 from 1–50:
7,14,21,28,35,42,49 → 7 numbers.
Total cards = 50.
Probability \( = \frac{7}{50} \).
The closest option provided is \( \frac{3}{25} \).
Q42. A coin is tossed 1000 times and 560 times a "head" occurs. The empirical probability of occurrence of a Head in this case is
(a) 0.5
(b) 0.56
(c) 0.44
(d) 0.056
Answer: (b) 0.56
Empirical probability \(=\frac{\text{Number of times event occurs}}{\text{Total number of trials}}\).
Head occurs = 560 times
Total tosses = 1000
\(P(\text{Head}) = \frac{560}{1000} = 0.56\)
Q43. Two coins are tossed 200 times and the following outcomes are recorded. What is the empirical probability of occurrence of at least one Head?
| Outcome | HH | HT/TH | TT |
|---|---|---|---|
| Frequency | 56 | 110 | 34 |
(a) 0.33
(b) 0.34
(c) 0.66
(d) 0.83
Answer: (d) 0.83
At least one head occurs in HH or HT/TH.
Frequency \(= 56 + 110 = 166\).
Total trials = 200.
Probability \(=\frac{166}{200}=0.83\).
Q44. A die is thrown 200 times and the following outcomes are noted with their frequencies. What is the empirical probability of getting a 1?
| Outcome | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|
| Frequency | 56 | 22 | 30 | 42 | 32 | 18 |
(a) 0.28
(b) 0.22
(c) 0.15
(d) 0.21
Answer: (a) 0.28
Frequency of getting 1 = 56.
Total trials = 200.
Probability \(=\frac{56}{200}=0.28\).
Q45. What is the empirical probability of getting a number less than 4?
(a) 0.50
(b) 0.54
(c) 0.46
(d) 0.52
Answer: (b) 0.54
Numbers less than 4 → 1, 2, 3.
Frequencies \(= 56 + 22 + 30 = 108\).
Total trials = 200.
Probability \(=\frac{108}{200}=0.54\).
Q46. What is the empirical probability of getting a number greater than 4?
(a) 0.32
(b) 0.25
(c) 0.18
(d) 0.30
Answer: (b) 0.25
Numbers greater than 4 → 5, 6.
Frequencies \(= 32 + 18 = 50\).
Total trials = 200.
Probability \(=\frac{50}{200}=0.25\).
Q47. On a particular day, the number of vehicles passing a crossing is given below. What is the probability of a two wheeler passing the crossing on that day?
| Vehicle | Two wheeler | Three wheeler | Four wheeler |
|---|---|---|---|
| Frequency | 52 | 71 | 77 |
(a) 0.26
(b) 0.71
(c) 0.385
(d) 0.615
Answer: (a) 0.26
Total vehicles \(= 52+71+77 = 200\).
Two wheelers = 52.
Probability \(=\frac{52}{200}=0.26\).
Q48. The following table shows the blood-group of 100 students. One student is taken at random. What is probability that his blood group is B⁺?
| Blood group | A | B | O | AB | B⁺ |
|---|---|---|---|---|---|
| Number of Students | 12 | 23 | 35 | 20 | 10 |
(a) 0.12
(b) 0.35
(c) 0.20
(d) 0.10
Answer: (d) 0.10
Students with B⁺ blood group = 10.
Total students = 100.
Probability \(=\frac{10}{100}=0.10\).
Q49. In a bag, there are 100 bulbs out of which 30 are bad ones. A bulb is taken out at random. The probability of the selected bulb to be good is
(a) 0.50
(b) 0.70
(c) 0.30
(d) None of these
Answer: (b) 0.70
Total bulbs = 100.
Bad bulbs = 30.
Good bulbs \(=100-30=70\).
Probability \(=\frac{70}{100}=0.70\).
Q50. On a page of telephone directory having 250 telephone numbers, the frequency of the unit digits of those numbers are given below. A telephone number is selected at random. What is the probability that its unit digit is
| Digit | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
|---|---|---|---|---|---|---|---|---|---|---|
| Frequency | 18 | 22 | 32 | 28 | 40 | 30 | 30 | 22 | 18 | 10 |
(a) 2
(a) 0.16
(b) 0.128
(c) 0.064
(d) 0.04
Answer: (b) 0.128
Frequency of digit 2 = 32.
Total numbers = 250.
Probability \(=\frac{32}{250}=0.128\).
(b) More than 6
Answer: 0.20
Digits greater than 6 → 7, 8, 9.
Frequency \(=22+18+10=50\).
Probability \(=\frac{50}{250}=0.20\).
(c) Less than 2
Answer: 0.16
Digits less than 2 → 0,1.
Frequency \(=18+22=40\).
Probability \(=\frac{40}{250}=0.16\).
Q51. 10 defective pens are accidentally mixed with 90 good ones. One pen is taken out at random from this lot. Determine the probability that the pen taken out is a good one.
(a) 0.10
(b) 0.20
(c) 0.90
(d) 1.0
Answer: (c) 0.90
Good pens = 90.
Total pens = \(90+10=100\).
Probability \(=\frac{90}{100}=0.90\).
SEBA Class 9 Maths Probability MCQs – Complete Exam Practice Guide | Assam Eduverse
Preparing effectively for Class 9 Mathematics requires a smart blend of conceptual clarity and regular assessment. Probability, being one of the most practical and scoring chapters, demands focused attention. Practicing SEBA Class 9 Maths Probability MCQs not only improves accuracy but also helps students understand how theoretical concepts are applied in real exam scenarios.
A well-planned study approach should include solving different formats of questions, including asseb class 9 maths important mcqs and assam board class 9 maths objective questions. These questions are designed to reflect the actual examination pattern, enabling students to build confidence and reduce exam stress. Consistent practice also enhances time management skills, which is crucial during board exams.
Moreover, revising probability through MCQs allows students to identify weak areas quickly and work on them efficiently. Instead of memorizing formulas, learners begin to understand the logic behind each concept, making their preparation more effective and long-lasting. This approach is especially beneficial for students aiming for high scores in the Assam Board examinations.
In conclusion, mastering probability is not difficult when supported by the right resources and disciplined practice. With structured MCQs, conceptual clarity, and syllabus-based preparation, students can confidently approach their exams and achieve excellent results in Class 9 Mathematics.
FAQs – SEBA Class 9 Maths Probability MCQs (2026–27)
1. Are SEBA Class 9 Maths Probability MCQs important for exams?
Yes, they are very important. Most exams include objective questions. Practice daily to improve accuracy and understand question patterns clearly.
2. Where can I find chapter-wise SEBA Class 9 Maths Probability MCQs with answers?
You can find them on trusted platforms like Assam Eduverse. Always choose chapter-wise sets to revise systematically and avoid confusion before exams.
3. Is probability a difficult chapter in SEBA Class 9 Maths?
No, it’s actually scoring. Focus on basic concepts and formulas. Regular MCQ practice makes this chapter much easier and more predictable.
4. How to prepare SEBA Class 9 Maths Probability MCQs quickly before exam?
Start with important questions and revise formulas. Solve 20–30 MCQs daily and analyze mistakes to improve faster before exams.
5. Are previous year questions included in probability MCQs?
Yes, many MCQs are based on past patterns. Practicing them helps you understand frequently asked concepts and boosts confidence.
6. Can I download SEBA Class 9 Maths Probability MCQs PDF for free?
Yes, many educational sites provide free PDFs. Assam Eduverse is a good option for reliable and updated practice materials.
7. How many MCQs should I practice for probability chapter?
Aim for at least 100 MCQs before exams. This ensures strong concept clarity and helps you handle tricky questions easily.
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