Class 10 SEBA Science Chapter 5 Solutions – Periodic Classification of Elements (2026–27) | Assam Eduverse
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SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions are prepared by Assam Eduverse strictly according to the latest SEBA / ASSEB syllabus 2026–27. These SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions are created for students searching specifically for SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions that are accurate, updated, and exam-oriented. This page provides complete SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions, making it a trusted source for SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions based on the official SEBA Class 10 Science textbook.
The SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions explain all concepts included in SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions, such as early attempts at classification, Dobereiner’s triads, Newlands’ law of octaves, Mendeleev’s periodic table, and the modern periodic table. These SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions also explain trends in the periodic table like atomic size, valency, metallic and non-metallic character, and periodicity using SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions written in simple and exam-friendly language, following the ASSEB Class 10 Science Chapter 5 solutions format.
With the complete SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions (2026–27), students can prepare SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions for intext questions and SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions for chapter-end textbook exercise questions. These SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solutions include important question answers, periodic trends explanations, and exam-focused notes. Assam Eduverse ensures every SEBA Class 10 Science Chapter 5 Periodic Classification of Elements solution is syllabus-based and exam-focused.
SEBA / ASSEB Class 10 Science Chapter 5 – Periodic Classification of Elements Intext Questions & Answers (Latest Syllabus 2026–27)
Page 81
Q1. Did Dobereiner’s triads also exist in the columns of Newlands’ Octaves ? Compare and find out.
Answer:
Yes, Dobereiner’s triads also existed in the columns of Newland’s Octaves.
For example, Li, Na, K.
If we consider lithium as the first element, then sodium is eighth element. If we consider sodium as the first element, then potassium is the eighth element.
Q2. What were the limitations of Dobereiner’s classification ?
Answer:
The limitations of Dobereiner’s classification are:
It could be applied to three triads.
Many elements could not be grouped into triads.
The atomic mass of the middle element was not the exact average of the other two in some cases.
Q3. What were the limitations of Newlands’ law of octaves ?
Answer:
The limitations of Newlands’ Law of Octaves are:
It worked well only for lighter elements upto calcium
Elements with different properties were sometimes placed in the same group.
Newlands forced the pattern even when it did not fit well, leading to incorrect grouping. For example, cobalt (Co) and nickel (Ni)
Newlands assumed that only 56 elements existed in nature and no more elements would be discovered in the future. But later oon several new elements were discovered
Iron (Fe) element which resemble elements like cobalt and nickel in properties, was placed far away from these elements.
Page 85
Q1. Use Mendeleev’s Periodic Table to predict the formulae for the oxides of the following elements : K, C, Al, Si, Ba
Answer:
K2O, CO2, Al2O3, SiO2, BaO.
Q2. Besides gallium, which other elements have since been discovered that were left by Mendeleev in his periodic table ? (any two)
Answer:
Scandium and Germanium.
Q3. What were the criteria used by Mendeleev in creating his Periodic Table ?
Answer:
Mendeleev used the relationship between the atomic masses of the elements and their physical and chemical properties. He used similarity in physical properties, similarity in the formation of hydrides and oxides of element.
Q4. Why do you think the noble gases are placed in a separate group ?
Answer:
Noble gases are placed in a separate group because they have very different properties from other elements. They are inert or chemically unreactive due to their complete outer electron shells. Unlike other elements, noble gases do not easily form compounds because their atoms are stable on their own. This unique behavior sets them apart, so they are grouped separately in the periodic table.
Page 90
Q1. How could the modern periodic table remove various anomalies of Mendeleev’s periodic Table ?
Answer:
The modern periodic table is based on the atomic number of elements, unlike Mendeleev’s table which was arranged by atomic mass. This change solved many anomalies because the atomic number reflects the number of protons, which determines an element’s properties. For example, Mendeleev placed some elements out of order based on atomic mass, but in the modern table, these elements are correctly arranged according to their atomic numbers. The modern table also includes the noble gases, which were missing in Mendeleev’s table, and groups elements more accurately based on their chemical behavior.
Q2. Name two elements you would expect to show chemical reactions similar to magnesium. What is the basis for your choice ?
Answer:
Beryllium (Be) and Calcium (Ca).
Both Be and Ca have similar electronic configuration, i.e. two electrons in outermost shells.
Be = 2,2
Ca =2, 8, 8, 2
Both Be and Ca react with oxygen to give basic oxides, BeO and MgO.
Q3. Name :
(a) three elements that have a single electron in their outermost shells.
(b) two elements that have two electrons in their outermost shells.
(c) three elements with filled outer most shells.
Answer:
(a) Lithium : Atomic number = 3(2, 1); Sodium : Atomic number =11(2, 8, 1); Potassium : Atomic number = 19(2, 8, 8, 1).
(b) Beryllium : Atomic number = 4(2, 2); Calcium : Atomic number = 20(2, 8, 8, 2)
(c) Helium : Atomic number =2(2); Neon : Atomic number – 10(2, 8); Argon : Atomic number – 18(2, 8, 8).
Q4.(a) Lithium, sodium, potassium are all metals that react with water to liberate hydrogen gas. Is there any similarity in the atoms of these elements ?
(b) Helium is an unreactive gas and neon is a gas of extremely low reactivity. What, if anything, do their atoms have in common ?
Answer
(a) Lithium, sodium, and potassium all belong to the same group in the periodic table (alkali metals). Their atoms each have one electron in their outermost shell, which makes them highly reactive and able to react with water to release hydrogen gas.
(b) Helium and neon are noble gases, meaning their atoms have completely filled outer electron shells. This makes them very stable and unreactive because they do not easily lose, gain, or share electrons with other elements.
Q5. In the modern periodic table, which are the metals among the first ten elements ?
Answer:The first ten elements in modern periodic table are hydrogen, helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine and neon. Out of these, lithium, beryllium and boron are metals, because they have 1, 2 and 3 electrons respectively in their outermost shells.
Q6. By considering their position in the Periodic Table, which one of the following elements would you expect to have maximum metallic characteristics ?
Ga, Ge, As, Se, Be
Answer:
Beryllium (Be). In the periodic table, the elements placed on the left show maximum metallic characteristics. Since beryllium occupies the most left position in comparison to other elements, hence it shows maximum metallic characteristics.
SEBA Class 10 Science Chapter 5 – Periodic Classification of Elements Textbook Exercise Questions & Solutions | 2026–27
Q1. Which of the following statements is not a correct statement about the trends while going from left to right across the periods of Periodic Table.
(a) The elements become less metallic in nature.
(b) The number of valence electrons increases.
(c) The atoms lose their electrons more easily.
(d) The oxides become more acidic.
Answer:
(c) The atoms lose their .electrons more easily.
Q2. Element X forms a chloride with the formula XCl2, which is solid with a high melting point. X would most likely to be in the same group of the periodic table as
(a) Na
(b) Mg
(c) Al
(d) Si
Answer:
(b) Mg
Q3. Which element has
(a) two shells, both of which are completely filled with electrons ?
(b) the electronic configuration 2, 8, 2 ?
(c) a total of three shells, with four electrons in its valence shell ?
(d) a total of two shells with three electrons in its valence shell. v
(e) twice as many electrons in its second shell as in its first shell ?
Answer:
(a) Neon (2, 8)
(b) Magnesium
(c) Silicon (2, 8, 4)
(d) Boron (2, 3)
(e) Carbon (2, 4)
Q4. (a) What property do all elements in the same column of the Periodic Table as boron have in common ?
(b) What property do all elements in the same column of the Periodic Table . as fluorine have in common ?
Answer:
(a) Elements in the same column or group as boron have valency of three and have three valence electrons.
(b) Elements in the same column or group as fluorine form acidic oxides and have seven electrons in their outermost shells and have valency of one.
Q5. An atom has electronic configuration 2, 8, 7.
(a) What is the atomic number of this element ?
(b) To which of the following elements would it be chemically similar ? (Atomic numbers are given in parentheses.)
N (7), F (9), P (15), Ar (18)
Answer:
(a) The atomic number of the given element is 2 + 8 + 7(= 17).
(b) It would be chemically similar to fluorine [F(9)] because its electronic configuration is 2, 7.
Q6. The positions of three elements A, B and C in the periodic table are shown below :
(a) State whether A is a metal or non-metal.
| Group 16 | Group 17 |
| – | – |
| – | A |
| – | – |
| B | C |
(b) State whether C is more reactive or less reactive than A.
(c) Will C be larger or smaller in size than B ?
(d) Which type of ion, cation or anion, will be formed by element A ?
Answer:
(a) Since the valency of group 17 elements is 1 and all these elements accept electrons, thus A is a non-metal.
(b) C is less reactive than A because as we move down in a group, the reactivity of non-metals increases.
(c) C is smaller in size than B because B and C both are related to the same period and the size decreases as one moves from left to right in a period.
(d) A will form anion because it is a non-metal.
Q7. Nitrogen (atomic number 7) and phosphorus (atomic number 15) belong to group 15 of the periodic table. Write the electronic configuration of these two elements. Which of these will be more electronegative ? Why ?
Answer:
Electronic configuration of nitrogen -2,5
Electronic configuration of phosphorus = 2, 8, 5
Nitrogen will be more electronegative because outermost shell is nearer to nucleus and therefore nucleus will attract electrons more strongly. In a group of the periodic table, electron attracting tendency decreases as we move from top to bottom.
Q8. How does the electronic configuration of an atom relate to its position in the Modern Periodic Table ?
Answer:The electronic configuration of an atom helps determine its exact position in the Modern Periodic Table. The number of shells in an atom tells us the period in which the element is placed, while the number of electrons in the outermost shell (valence electrons) determines the group of the element. For example, if an element has two shells and one electron in the outermost shell (like lithium with configuration 2,1), it is placed in Period 2 and Group 1. This pattern holds true across the table, making electronic configuration a key to understanding the table’s structure.
Q9. In the Modern Periodic Table, calcium (atomic number 20) is surrounded by elements with atomic number 12, 19, 21 and 38. Which of these have physical and chemical properties resembling calcium ?
Answer:
The electronic configuration of elements with :
Atomic number 12 = 2, 8, 2
Atomic number 19 = 2, 8, 8, 1
Atomic number 20 = 2, 8, 8, 2
Atomic number 21 = 2, 8, 9, 2
Atomic number 38 = 2, 8, 18, 8, 2
Elements with atomic number 12 i.e., magnesium (Mg) and 38 i.e., strontium (Sr) will have similar physical and chemical properties as element with atomic numbers 20 i.e., calcium (Ca).
Q10. Compare and contrast the arrangement of elements in Mendeleev’s Periodic Table and the Modern Periodic Table.
Answer:
| Mendeleev’s Periodic Table | Modern Periodic Table |
| (i) Elements are arranged in the order of increasing atomic mass. | (i) Elements are arranged in the order of increasing atomic number. |
| (ii) There are nine vertical columns called groups. | (ii) There are eighteen vertical columns called groups. |
| (iii) There is no place for noble gases. | (iii) Noble gases are placed on the right hand side of the table. |
| (iv) There is no place for isotopes. | (iv) Isotope are kept at the same place because their atomic number is same. |
| (v) Transition elements are placed together in group VIII. | (v) Transition elements are placed in the middle of the long period (Group 3 to 12). |
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