Class 10 Chapter 12 Electricity PYQs

SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions | Assam Eduverse

SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions are prepared to help students master electric current, potential difference, and resistance for the HSLC examination. These SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions include numerical problems, formula-based questions, previous year questions (PYQs), and important MCQs.

The SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions strictly follow the latest SEBA (ASSEB) syllabus for 2026–27. Since students must answer 45 MCQs in the HSLC Science examination, practising MCQs from SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions is essential.

Topics covered in SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions include Ohm’s Law, resistance, factors affecting resistance, series and parallel combination of resistors, electric power, and heating effect of current. Students searching for HSLC Science Chapter 12 Electricity Important Questions or SEBA Class 10 Science Chapter 12 PYQs will find this resource highly beneficial for exam preparation.

SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions

Table of Contents

A. Previous Year Questions with Answers

Q1. The unit of specific resistance of a material in S.I. system is — [HSLC 2015]
(i) Ω
(ii) Ω m
(iii) Ω m⁻¹
(iv) Ω m²
Answer: (ii) Ω m

Q2. A piece of wire of resistance 2 Ω is cut into four equal parts. These parts are then connected in parallel. If R denotes the equivalent resistance of the parallel combination, then 2 Ω : R is — [HSLC 2015]
(i) 16
(ii) 4
(iii) 2
(iv) 8
Answer: (i) 16

Q3. Two wires have lengths, resistances, resistivities — each in the ratio 1 : 2. What is the ratio of their diameters? — [HSLC 2016]
(i) 1 : √2
(ii) 1 : 4
(iii) 4 : 1
(iv) 1 : 3
Answer: (i) 1 : √2

Q4. How many electrons will contribute in one second in causing one micro-ampere of current? — [HSLC 2017]
(i) 6.25 × 10¹⁵
(ii) 6.25 × 10⁹
(iii) 6.25 × 10¹²
(iv) 6.25 × 10⁶
Answer: (iii) 6.25 × 10¹²

Q5. An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, then the power consumed is — [HSLC 2018]
(i) 75 W
(ii) 25 W
(iii) 100 W
(iv) 50 W
Answer: (ii) 25 W

Q6. The practical unit of electrical energy kWh means — [HSLC 2019]
(i) 36 × 10⁶ J
(ii) 3.6 × 10⁶ J
(iii) 3.6 × 10⁵ J
(iv) 36 × 10⁴ J
Answer: (ii) 3.6 × 10⁶ J

Q7. Which of the following terms does not represent electrical power in a circuit? — [HSLC 2020]
(i) IR²
(ii) I²R
(iii) V²/R
(iv) VI
Answer: (i) IR²

Q8. The SI unit of electric charge is — [HSLC 2022]
(i) coulomb
(ii) volt
(iii) watt
(iv) joule
Answer: (i) coulomb

Q9. Which of the following is used to measure the potential difference of a circuit? — [HSLC 2023]
(i) Ammeter
(ii) Voltmeter
(iii) Galvanometer
(iv) Multimeter
Answer: (ii) Voltmeter

Q10. In an experiment, the variation of current with the applied voltage for a conducting material is obtained as shown below: Which of the following conclusions is/are true about the conductor? [HSLC 2024]
(i) Current increases linearly with the voltage.
(ii) Resistance is different for different values of V.
(iii) The slope of the graph is same for every value of V and I.
(A) (i) only
(B) (i) and (iii)
(C) (ii) only
(D) (i) and (ii)
Answer: (C) (ii) only

Q11. 1 kWh = ______ joule [HSLC 2024]
(A) 3.6 × 10⁵
(B) 3.6 × 10⁶
(C) 3.6 × 10⁷
(D) 3.6 × 10⁸
Answer: (B) 3.6 × 10⁶

Q12. 1 eV = ______ [HSLC 2024]
(A) 1.602 × 10⁻¹⁸ J
(B) 1.602 × 10⁻¹⁹ J
(C) 1.601 × 10⁻¹⁷ J
(D) 1.601 × 10⁻¹⁶ J
Answer: (B) 1.602 × 10⁻¹⁹ J

Q13. A current of 0·5 A is drawn by a filament of an electric bulb for 10 minutes. The amount of electric charge that flows through the circuit is [HSLC 2024]
(A) 330 C
(B) 310 C
(C) 320 C
(D) 300 C
Answer: (D) 300 C

Q14. Electrical appliances that have metal body are generally connected to the earthing wire. What is the reason to earth the wire? [HSLC 2025]
(a) To prevent the excess of current
(b) To prevent the leakage of current
(c) To prevent the extra current to the appliances
(d) To prevent high resistance to the appliances
Answer: (b) To prevent the leakage of current

Q15. An electric bulb is connected to a 200 V generator. The current is 0·4 A. What is the power of the bulb? [HSLC 2025]
(a) 100 W
(b) 90 W
(c) 80 W
(d) 110 W
Answer: (c) 80 W

Q16. Which of the following terms does not represent electrical power in a circuit? [HSLC 2025]
(a) I²R
(b) V²/R
(c) VI
(d) IR²
Answer: (d) IR²

Q17. Studying Ohm’s law (V = IR), a student prepared the following table: [HSLC 2025]

V (in volt): 0·4 0·8 1·2 Y
I (in ampere): 0·1 0·2 X 0·5

The respective value of X and Y will be
(a) 0·3 and 2
(b) 0·1 and 0·4
(c) 0·3 and 1·6
(d) 0·4 and 1·8
Answer: (c) 0·3 and 1·6

B. Extra Questions with Answers

Q1. What is meant by an electric circuit?
(i) A device that produces electricity
(ii) A continuous and closed path of electric current
(iii) A source of potential difference
(iv) A conductor carrying charges
Answer: (ii) A continuous and closed path of electric current.

Q2. The SI unit of electric current is —
(i) Volt
(ii) Ohm
(iii) Ampere
(iv) Coulomb
Answer: (iii) Ampere.

Q3. If 1 coulomb of charge flows through a conductor in 1 second, the current is —
(i) 1 volt
(ii) 1 ampere
(iii) 1 ohm
(iv) 1 watt
Answer: (ii) 1 ampere.

Q4. The potential difference between two points is 1 V if —
(i) 1 A current flows between them
(ii) 1 J of work is done in moving 1 C of charge
(iii) 1 C of charge flows in 1 s
(iv) 1 W power is consumed
Answer: (ii) 1 J of work is done in moving 1 C of charge.

Q5. A voltmeter is connected in a circuit —
(i) In series with the component
(ii) In parallel across the component
(iii) In series with the battery
(iv) In parallel with the ammeter
Answer: (ii) In parallel across the component.

Q6. Assertion (A): In a series combination of resistors, the current is the same through each resistor.
Reason (R): In a series circuit, there is only one path for the flow of current.

(i) Both A and R are true and R is the correct explanation of A.
(ii) Both A and R are true but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A is false but R is true.
Answer: (i) Both A and R are true and R is the correct explanation of A.

Q7. When studying the relationship between potential difference and current using a nichrome wire, the graph between V and I is —
(i) A curve
(ii) A straight line passing through origin
(iii) A circle
(iv) A straight line not passing through origin
Answer: (ii) A straight line passing through origin.

Q8. Match the following:

Column I | Column II
(a) Ammeter | (1) Measures potential difference
(b) Voltmeter | (2) Measures current
(c) Rheostat | (3) Regulates current
(d) Ohm | (4) Unit of resistance

(i) (a–2), (b–1), (c–3), (d–4)
(ii) (a–1), (b–2), (c–4), (d–3)
(iii) (a–2), (b–3), (c–1), (d–4)
(iv) (a–3), (b–1), (c–2), (d–4)
Answer: (i) (a–2), (b–1), (c–3), (d–4).

Q9. The resistance of a conductor depends on —
(i) Length of the conductor
(ii) Area of cross-section
(iii) Nature of material
(iv) All of these
Answer: (iv) All of these.

Q10. In an experiment, when the length of a nichrome wire is doubled keeping other factors constant, the resistance —
(i) Becomes half
(ii) Remains same
(iii) Becomes double
(iv) Becomes one-fourth
Answer: (iii) Becomes double.

Q11. According to Ohm’s law, the potential difference across the ends of a metallic conductor is directly proportional to —
(i) Resistance
(ii) Current
(iii) Length
(iv) Area of cross-section
Answer: (ii) Current.

Q12. The SI unit of resistance is —
(i) Volt
(ii) Ampere
(iii) Ohm
(iv) Watt
Answer: (iii) Ohm.

Q13. Assertion (A): The resistance of a uniform metallic conductor is inversely proportional to its area of cross-section.
Reason (R): A thicker wire offers less resistance to the flow of current.

(i) Both A and R are true and R is the correct explanation of A.
(ii) Both A and R are true but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A is false but R is true.
Answer: (i) Both A and R are true and R is the correct explanation of A.

Q14. When three resistors are connected in series, the equivalent resistance is —
(i) Less than the smallest resistance
(ii) Equal to the average of the resistances
(iii) Equal to the sum of individual resistances
(iv) Equal to the product of the resistances
Answer: (iii) Equal to the sum of individual resistances.

Q15. In a parallel combination of resistors, the potential difference across each resistor is —
(i) Different
(ii) Zero
(iii) Same
(iv) Double
Answer: (iii) Same.

Q16. If three resistors 2 Ω, 3 Ω and 6 Ω are connected in parallel, the equivalent resistance is —
(i) 11 Ω
(ii) 1 Ω
(iii) 6 Ω
(iv) 2 Ω
Answer: (ii) 1 Ω.

Q17. Match the following:

Column I | Column II
(a) Series combination | (1) Current divides
(b) Parallel combination | (2) Current same
(c) Equivalent resistance in series | (3) Less than smallest resistance
(d) Equivalent resistance in parallel | (4) Sum of resistances

(i) (a–2), (b–1), (c–4), (d–3)
(ii) (a–1), (b–2), (c–3), (d–4)
(iii) (a–2), (b–1), (c–3), (d–4)
(iv) (a–4), (b–3), (c–2), (d–1)
Answer: (i) (a–2), (b–1), (c–4), (d–3).

Q18. When different components like nichrome wire, torch bulb and 10 W bulb are connected one by one in the same circuit, the ammeter readings are different because —
(i) Current is constant in all cases
(ii) Each component offers different resistance
(iii) Voltage changes automatically
(iv) Battery strength increases
Answer: (ii) Each component offers different resistance.

Q19. Assertion (A): Alloys are used in electrical heating devices.
Reason (R): Alloys have higher resistivity and do not oxidise readily at high temperature.

(i) Both A and R are true and R is the correct explanation of A.
(ii) Both A and R are true but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A is false but R is true.
Answer: (i) Both A and R are true and R is the correct explanation of A.

Q20. The resistivity of a material depends on —
(i) Length of the conductor
(ii) Area of cross-section
(iii) Nature of the material
(iv) Shape of the conductor
Answer: (iii) Nature of the material.

Q21. The heat produced in a resistor is directly proportional to —
(i) Current
(ii) Square of current
(iii) Resistance only
(iv) Voltage only
Answer: (ii) Square of current.

Q22. According to Joule’s law of heating, H = —
(i) VIt
(ii) I²Rt
(iii) V²t/R
(iv) All of these
Answer: (iv) All of these.

Q23. Assertion (A): When current flows through a purely resistive circuit, electrical energy is dissipated entirely in the form of heat.
Reason (R): In a purely resistive circuit, there is no device to convert electrical energy into other forms of energy.

(i) Both A and R are true and R is the correct explanation of A.
(ii) Both A and R are true but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A is false but R is true.
Answer: (i) Both A and R are true and R is the correct explanation of A.

Q24. The commercial unit of electrical energy is —
(i) Watt
(ii) Joule
(iii) Kilowatt hour
(iv) Watt second
Answer: (iii) Kilowatt hour.

Q25. 1 kWh is equal to —
(i) 3.6 × 10⁶ J
(ii) 3.6 × 10⁵ J
(iii) 36 × 10⁶ J
(iv) 3.6 × 10³ J
Answer: (i) 3.6 × 10⁶ J.

Q26. Electric power is given by —
(i) VI
(ii) I²R
(iii) V²/R
(iv) All of these
Answer: (iv) All of these.

Q27. Match the following:

Column I | Column II
(a) Electric power | (1) Watt
(b) Electric energy | (2) VIt
(c) Joule’s law | (3) Rate of doing work
(d) 1 kWh | (4) 3.6 × 10⁶ J

(i) (a–3), (b–2), (c–4), (d–1)
(ii) (a–1), (b–3), (c–2), (d–4)
(iii) (a–3), (b–2), (c–1), (d–4)
(iv) (a–2), (b–1), (c–3), (d–4)
Answer: (iii) (a–3), (b–2), (c–1), (d–4).

Q28. The filament of an electric bulb is made of tungsten because —
(i) It has low melting point
(ii) It has high resistivity and high melting point
(iii) It is a good conductor only
(iv) It is inexpensive
Answer: (ii) It has high resistivity and high melting point.

Q29. A fuse wire is connected in a circuit —
(i) In parallel
(ii) In series
(iii) Across the battery
(iv) With the voltmeter
Answer: (ii) In series.

Q30. In domestic circuits, electrical appliances are connected in parallel because —
(i) The same current flows through each appliance
(ii) The potential difference across each appliance is same
(iii) The resistance becomes maximum
(iv) Power consumption becomes zero
Answer: (ii) The potential difference across each appliance is same.

Q31. If the resistance of a conductor is doubled while keeping the potential difference constant, the current will —
(i) Become double
(ii) Become half
(iii) Remain same
(iv) Become four times
Answer: (ii) Become half.

Q32. When a number of resistors are connected in series, the equivalent resistance is always —
(i) Less than the smallest resistance
(ii) Equal to the largest resistance
(iii) Greater than any individual resistance
(iv) Zero
Answer: (iii) Greater than any individual resistance.

Q33. In a parallel combination of resistors, the equivalent resistance is —
(i) Greater than the largest resistance
(ii) Less than the smallest resistance
(iii) Equal to the sum of resistances
(iv) Infinite
Answer: (ii) Less than the smallest resistance.

Q34. Assertion (A): The current through each resistor in a parallel circuit is different.
Reason (R): The potential difference across each resistor in parallel is the same.

(i) Both A and R are true and R is the correct explanation of A.
(ii) Both A and R are true but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A is false but R is true.
Answer: (ii) Both A and R are true but R is not the correct explanation of A.

Q35. The resistivity of a material is —
(i) Dependent on length and area
(ii) Independent of material
(iii) A characteristic property of the material
(iv) Equal to resistance
Answer: (iii) A characteristic property of the material.

Q36. Match the following:

Column I | Column II
(a) Ampere | (1) Unit of potential difference
(b) Volt | (2) Unit of current
(c) Ohm | (3) Unit of resistance
(d) Watt | (4) Unit of power

(i) (a–2), (b–1), (c–3), (d–4)
(ii) (a–1), (b–2), (c–4), (d–3)
(iii) (a–2), (b–3), (c–1), (d–4)
(iv) (a–4), (b–3), (c–2), (d–1)
Answer: (i) (a–2), (b–1), (c–3), (d–4).

Q37. The heating element of an electric iron is made of an alloy because it —
(i) Has low resistance
(ii) Melts easily
(iii) Has high resistivity and does not oxidise readily
(iv) Is a good insulator
Answer: (iii) Has high resistivity and does not oxidise readily.

Q38. If the area of cross-section of a wire is increased, its resistance —
(i) Increases
(ii) Decreases
(iii) Remains same
(iv) Becomes zero
Answer: (ii) Decreases.

Q39. The direction of conventional current in a metallic conductor is —
(i) Same as the direction of flow of electrons
(ii) Opposite to the direction of flow of electrons
(iii) From negative to positive terminal inside the cell
(iv) Random
Answer: (ii) Opposite to the direction of flow of electrons.

Q40. When a wire of length l and resistance R is cut into two equal parts and connected in parallel, the equivalent resistance is —
(i) R
(ii) R/2
(iii) R/4
(iv) 2R
Answer: (iii) R/4.

Q41. The potential difference across a conductor is 6 V and the current through it is 2 A. The resistance of the conductor is —
(i) 3 Ω
(ii) 12 Ω
(iii) 4 Ω
(iv) 0.33 Ω
Answer: (i) 3 Ω.

Q42. If three resistors of 4 Ω each are connected in series, the equivalent resistance is —
(i) 4 Ω
(ii) 8 Ω
(iii) 12 Ω
(iv) 16 Ω
Answer: (iii) 12 Ω.

Q43. If three resistors of 4 Ω each are connected in parallel, the equivalent resistance is —
(i) 12 Ω
(ii) 4 Ω
(iii) 4/3 Ω
(iv) 1 Ω
Answer: (iii) 4/3 Ω.

Q44. Assertion (A): In a series circuit, if one component fails, the entire circuit stops working.
Reason (R): In a series circuit, components are connected one after another forming a single path.

(i) Both A and R are true and R is the correct explanation of A.
(ii) Both A and R are true but R is not the correct explanation of A.
(iii) A is true but R is false.
(iv) A is false but R is true.
Answer: (i) Both A and R are true and R is the correct explanation of A.

Q45. The amount of heat produced in a resistor depends on —
(i) Current
(ii) Resistance
(iii) Time
(iv) All of these
Answer: (iv) All of these.

Q46. 1 watt is equal to —
(i) 1 V/A
(ii) 1 V × 1 A
(iii) 1 A/1 V
(iv) 1 J
Answer: (ii) 1 V × 1 A.

Q47. Match the following:

Column I | Column II
(a) Electric fuse | (1) Protects circuit
(b) Tungsten | (2) Bulb filament
(c) Nichrome | (3) Heating element
(d) kWh | (4) Commercial unit of energy

(i) (a–1), (b–2), (c–3), (d–4)
(ii) (a–2), (b–3), (c–1), (d–4)
(iii) (a–3), (b–1), (c–2), (d–4)
(iv) (a–1), (b–3), (c–2), (d–4)
Answer: (i) (a–1), (b–2), (c–3), (d–4).

Q48. The power consumed by a device is 220 W when operated at 220 V. The current drawn by the device is —
(i) 1 A
(ii) 2 A
(iii) 0.5 A
(iv) 220 A
Answer: (i) 1 A.

Q49. If 3.6 × 10⁶ J of energy is consumed, it is equal to —
(i) 1 kWh
(ii) 10 kWh
(iii) 0.1 kWh
(iv) 100 kWh
Answer: (i) 1 kWh.

Q50. The resistance of a wire is directly proportional to —
(i) Area of cross-section
(ii) Square of area
(iii) Length of the wire
(iv) Nature of material only
Answer: (iii) Length of the wire.

Numericals based  MCQs with solutions

 

Q1. Three resistors of 2 Ω, 3 Ω and 5 Ω are connected in series to a 10 V battery. The current in the circuit is —
(i) 1 A
(ii) 2 A
(iii) 0.5 A
(iv) 5 A
Answer: (i) 1 A.
Solution:
Rs = 2 + 3 + 5 = 10 Ω
I = V/Rs = 10/10 = 1 A


Q2. Two resistors of 4 Ω and 6 Ω are connected in series to a 20 V source. The potential difference across 6 Ω resistor is —
(i) 12 V
(ii) 8 V
(iii) 6 V
(iv) 10 V
Answer: (i) 12 V.
Solution:
Rs = 4 + 6 = 10 Ω
I = 20/10 = 2 A
V₂ = IR = 2 × 6 = 12 V


Q3. Three resistors 3 Ω, 6 Ω and 2 Ω are connected in parallel. The equivalent resistance is —
(i) 1 Ω
(ii) 2 Ω
(iii) 3 Ω
(iv) 6 Ω
Answer: (i) 1 Ω.
Solution:
1/Rp = 1/3 + 1/6 + 1/2
= 2/6 + 1/6 + 3/6 = 6/6
Rp = 1 Ω


Q4. A 12 V battery is connected to a 4 Ω resistor. The current through the resistor is —
(i) 3 A
(ii) 4 A
(iii) 2 A
(iv) 6 A
Answer: (i) 3 A.
Solution:
I = V/R = 12/4 = 3 A


Q5. Two resistors 8 Ω and 12 Ω are connected in parallel. The equivalent resistance is —
(i) 4.8 Ω
(ii) 20 Ω
(iii) 6 Ω
(iv) 10 Ω
Answer: (i) 4.8 Ω.
Solution:
1/Rp = 1/8 + 1/12
= 3/24 + 2/24 = 5/24
Rp = 24/5 = 4.8 Ω


Q6. Three resistors of 5 Ω each are connected in series to a 15 V battery. The total current is —
(i) 1 A
(ii) 3 A
(iii) 5 A
(iv) 15 A
Answer: (i) 1 A.
Solution:
Rs = 5 + 5 + 5 = 15 Ω
I = 15/15 = 1 A


Q7. Three resistors of 5 Ω each are connected in parallel to 15 V. The total current is —
(i) 3 A
(ii) 9 A
(iii) 1 A
(iv) 5 A
Answer: (b) 9 A.
Solution:
Rp = 5/3 Ω
I = V/Rp = 15/(5/3) = 15 × 3/5 = 9 A


Q8. A heater of resistance 20 Ω is connected to 220 V. The current drawn is —
(i) 11 A
(ii) 10 A
(iii) 5 A
(iv) 2 A
Answer: (a) 11 A.
Solution:
I = 220/20 = 11 A


Q9. A 6 V battery is connected across a 3 Ω resistor. The heat produced in 5 s is —
(i) 60 J
(ii) 120 J
(iii) 30 J
(iv) 90 J
Answer: (a) 60 J.
Solution:
I = 6/3 = 2 A
H = I²Rt = 4 × 3 × 5 = 60 J


Q10. Two resistors 10 Ω and 20 Ω are connected in parallel to 20 V. Total current is —
(i) 3 A
(ii) 2 A
(iii) 4 A
(iv) 1 A
Answer: (a) 3 A.
Solution:
I₁ = 20/10 = 2 A
I₂ = 20/20 = 1 A
I = 3 A


Q11. A bulb rated 100 W, 220 V draws current —
(i) 0.45 A
(ii) 2.2 A
(iii) 1 A
(iv) 0.1 A
Answer: (a) 0.45 A.
Solution:
I = P/V = 100/220 ≈ 0.45 A


Q12. A 5 Ω resistor carries 2 A current. Power consumed is —
(i) 20 W
(ii) 10 W
(iii) 5 W
(iv) 40 W
Answer: (a) 20 W.
Solution:
P = I²R = 4 × 5 = 20 W


Q13. Four resistors of 4 Ω each are connected in series. Equivalent resistance is —
(i) 4 Ω
(ii) 8 Ω
(iii) 16 Ω
(iv) 1 Ω
Answer: (c) 16 Ω.
Solution:
Rs = 4 + 4 + 4 + 4 = 16 Ω


Q14. Four resistors of 4 Ω each are connected in parallel. Equivalent resistance is —
(i) 1 Ω
(ii) 4 Ω
(iii) 16 Ω
(iv) 2 Ω
Answer: (a) 1 Ω.
Solution:
Rp = 4/4 = 1 Ω


Q15. A 9 V battery is connected to 3 Ω and 6 Ω in series. Current in circuit is —
(i) 1 A
(ii) 3 A
(iii) 2 A
(iv) 0.5 A
Answer: (a) 1 A.
Solution:
Rs = 9 Ω
I = 9/9 = 1 A


Q16. A 12 Ω resistor is connected to 6 V. Power consumed is —
(i) 3 W
(ii) 6 W
(iii) 12 W
(iv) 1 W
Answer: (a) 3 W.
Solution:
I = 6/12 = 0.5 A
P = VI = 6 × 0.5 = 3 W


Q17. A current of 0.5 A flows through 10 Ω resistor for 4 s. Heat produced is —
(i) 10 J
(ii) 20 J
(iii) 5 J
(iv) 40 J
Answer: (a) 10 J.
Solution:
H = I²Rt = 0.25 × 10 × 4 = 10 J


Q18. Two 6 Ω resistors in parallel have equivalent resistance —
(i) 3 Ω
(ii) 12 Ω
(iii) 6 Ω
(iv) 1 Ω
Answer: (a) 3 Ω.
Solution:
Rp = 6/2 = 3 Ω


Q19. A 220 V heater draws 5 A. Its resistance is —
(i) 44 Ω
(ii) 110 Ω
(iii) 220 Ω
(iv) 5 Ω
Answer: (a) 44 Ω.
Solution:
R = V/I = 220/5 = 44 Ω


Q20. A device consumes 600 W at 200 V. The current drawn is —
(i) 2 A
(ii) 3 A
(iii) 4 A
(iv) 5 A
Answer: (b) 3 A.
Solution:
I = P/V = 600/200 = 3 A

SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions for HSLC Exam 2026–27

The SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions provided here are prepared according to the latest SEBA (ASSEB) syllabus 2026–27. These SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions include conceptual MCQs, short answer questions, long answer questions, and numerical problems aligned with the HSLC exam pattern.

As per the latest HSLC structure, students must attempt 45 MCQs. Therefore, regular practice of SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions ensures strong preparation for MCQ-based and calculation-based questions.

The SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions cover Ohm’s Law derivations, V–I graphs, calculation of equivalent resistance, electric power formula, and heating effect of electric current. Continuous revision using SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions improves numerical accuracy and conceptual clarity.

These Class 10 Electricity Important Questions with MCQs are ideal for final revision. Consistent practice of SEBA Class 10 Science Chapter 12 Electricity Important Extra Questions strengthens exam confidence and scoring performance.

Frequently Asked Questions (FAQ)

1. Why is Chapter 12 Electricity important for HSLC exam?

This chapter includes numerical problems based on Ohm’s Law, resistance, electric power, and circuit combinations frequently asked in HSLC Science exams.

2. How many MCQs are asked in HSLC Science exam?

Students must answer 45 MCQs as per the latest HSLC Science examination pattern.

3. Are MCQs included in Electricity important questions?

Yes, important conceptual and numerical MCQs are included according to the updated HSLC exam structure.

4. Are these questions based on SEBA syllabus?

Yes, all questions are prepared strictly according to the latest SEBA (ASSEB) syllabus for 2026–27.

5. Do these include previous year questions?

Yes, previous year questions are included to help students understand HSLC exam trends.

6. Which topics are covered in Chapter 12?

Topics include Ohm’s Law, resistance calculation, series and parallel circuits, electric power, and heating effect of current.

7. Can practising these improve exam performance?

Yes, regular revision improves numerical accuracy, formula application, and MCQ performance in the HSLC examination.

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