SEBA Class 9 Maths Chapter 1 Number System MCQs (2026–27) – Assam Eduverse
A strong understanding of fundamentals begins with the SEBA Class 9 Maths Chapter 1 Number System MCQs, which are designed as per the latest ASSEB syllabus and follow the current academic session’s exam pattern. These SEBA Class 9 Maths Chapter 1 Number System MCQs include conceptual, objective, and exam-oriented questions that help students build a solid mathematical base. For additional practice, students can also refer to important maths MCQs chapter-wise.
Prepared by subject experts of Assam Eduverse, this set of seba class 9 maths chapter 1 mcqs focuses on key topics such as real numbers, rational and irrational numbers, number line representation, terminating and non-terminating decimals, laws of exponents, and operations on real numbers. Practicing number system mcqs class 9 seba along with chapterwise MCQs and question answers helps improve conceptual clarity and accuracy.
Consistent practice of these ASSEB Class 9 Maths Important MCQs strengthens preparation and boosts confidence in solving objective-type questions. Students can also explore complete Class 9 study materials for comprehensive learning.
SEBA Class 9 Maths Chapter 1 Number System MCQs – ASSEB 2026–27 Board Exam Practice
Table of Contents
Q1. Rational number \( \frac{3}{40} \) is equal to:
(a) 0.75
(b) 0.12
(c) 0.012
(d) 0.075
Answer: (d) 0.075
\( \frac{3}{40} = \frac{75}{1000} = 0.075 \)
Q2. A rational number between 3 and 4 is:
(a) \( \frac{3}{2} \)
(b) \( \frac{4}{3} \)
(c) \( \frac{7}{2} \)
(d) \( \frac{7}{4} \)
Answer: (c) \( \frac{7}{2} \)
\( \frac{7}{2} = 3.5 \), which lies between 3 and 4.
Q3. A rational number between \( \frac{3}{5} \) and \( \frac{4}{5} \) is:
(a) \( \frac{7}{5} \)
(b) \( \frac{7}{10} \)
(c) \( \frac{3}{10} \)
(d) \( \frac{4}{10} \)
Answer: (b) \( \frac{7}{10} \)
\( \frac{3}{5}=0.6,\; \frac{4}{5}=0.8,\; \frac{7}{10}=0.7 \).
0.7 lies between 0.6 and 0.8.
Q4. A rational number between \( \frac{1}{2} \) and \( \frac{3}{4} \) is:
(a) \( \frac{2}{5} \)
(b) \( \frac{5}{8} \)
(c) \( \frac{4}{3} \)
(d) \( \frac{1}{4} \)
Answer: (b) \( \frac{5}{8} \)
\( \frac{1}{2}=0.5,\; \frac{3}{4}=0.75,\; \frac{5}{8}=0.625 \).
0.625 lies between 0.5 and 0.75.
Q5. Which one of the following is not a rational number:
(a) \( \sqrt{2} \)
(b) 0
(c) \( \sqrt{4} \)
(d) \( \sqrt{-16} \)
Answer: (a) \( \sqrt{2} \)
\( \sqrt{2} \) cannot be written in the form \( \frac{p}{q} \).
So it is irrational.
Q6. Which one of the following is an irrational number:
(a) \( \sqrt{4} \)
(b) \( 3\sqrt{8} \)
(c) \( \sqrt{100} \)
(d) \( -\sqrt{0.64} \)
Answer: (b) \( 3\sqrt{8} \)
\( \sqrt{8}=2\sqrt{2} \Rightarrow 3\sqrt{8}=6\sqrt{2} \).
Since \( \sqrt{2} \) is irrational, \( 6\sqrt{2} \) is irrational.
Q7. Decimal representation of \( \frac{1}{5} \) is:
(a) 0.2
(b) 0.5
(c) 0.02
(d) 0.002
Answer: (a) 0.2
\( \frac{1}{5}=0.2 \)
Q8. \( 3\frac{3}{8} \) in decimal form is:
(a) 3.35
(b) 3.375
(c) 33.75
(d) 337.5
Answer: (b) 3.375
\( 3+\frac{3}{8}=3+0.375=3.375 \)
Q9. \( \frac{5}{6} \) in decimal form is:
(a) \( 0.8\overline{3} \)
(b) \( 0.\overline{83} \)
(c) \( 0.6\overline{3} \)
(d) \( 0.63\overline{3} \)
Answer: (a) \( 0.8\overline{3} \)
\( \frac{5}{6}=0.8333\ldots=0.8\overline{3} \)
Q10. Decimal representation of \( \frac{8}{27} \) is:
(a) \( 0.\overline{296} \)
(b) \( 0.29\overline{6} \)
(c) \( 0.2\overline{96} \)
(d) 0.296
Answer: (a) \( 0.\overline{296} \)
\( \frac{8}{27}=0.296296296\ldots \)
The block 296 repeats.
Q11. Which one of the following is a rational number:
(a) \( \sqrt{3} \)
(b) \( \sqrt{2} \)
(c) \( 0 \)
(d) \( \sqrt{5} \)
Answer: (c) \( 0 \)
A rational number can be written in the form \( \frac{p}{q} \).
\( 0 = \frac{0}{1} \). Hence, it is rational.
Q12. \( 0.6666\ldots \) in \( \frac{p}{q} \) form is:
(a) \( \frac{6}{99} \)
(b) \( \frac{2}{3} \)
(c) \( \frac{3}{5} \)
(d) \( \frac{1}{66} \)
Answer: (b) \( \frac{2}{3} \)
Let \( x = 0.6666\ldots \)
\( 10x = 6.6666\ldots \)
\( 10x - x = 6 \Rightarrow 9x = 6 \Rightarrow x = \frac{6}{9} = \frac{2}{3} \)
Q13. \( 4\frac{1}{8} \) in decimal form is:
(a) 4.125
(b) 4.15
(c) 4.015
(d) 0.4125
Answer: (a) 4.125
\( 4 + \frac{1}{8} = 4 + 0.125 = 4.125 \)
Q14. The value of \( (3 + \sqrt{3})(3 - \sqrt{3}) \) is:
(a) 0
(b) 6
(c) 9
(d) 3
Answer: (b) 6
Using \( (a+b)(a-b)=a^2-b^2 \):
\( 9 - 3 = 6 \)
Q15. The value of \( (\sqrt{5} + \sqrt{2})^2 \) is:
(a) \( 7 + 2\sqrt{5} \)
(b) \( 7 + 2\sqrt{10} \)
(c) \( 5 + 2\sqrt{10} \)
(d) \( 7 - 2\sqrt{10} \)
Answer: (b) \( 7 + 2\sqrt{10} \)
\( 5 + 2 + 2\sqrt{10} = 7 + 2\sqrt{10} \)
Q16. The value of \( (\sqrt{5} + \sqrt{2})(\sqrt{5} - \sqrt{2}) \) is:
(a) 10
(b) 7
(c) 3
(d) 5
Answer: (c) 3
\( 5 - 2 = 3 \)
Q17. The value of \( (3 + \sqrt{3})(2 + \sqrt{2}) \) is:
(a) \( 6 + 3\sqrt{2} + 2\sqrt{3} + \sqrt{6} \)
(b) \( 6 - 3\sqrt{2} + 2\sqrt{3} - \sqrt{6} \)
(c) \( 6 + 3\sqrt{2} - 2\sqrt{3} + \sqrt{6} \)
(d) \( 6 - 3\sqrt{2} - 2\sqrt{3} - \sqrt{6} \)
Answer: (a) \( 6 + 3\sqrt{2} + 2\sqrt{3} + \sqrt{6} \)
Multiply each term:
\( 6 + 3\sqrt{2} + 2\sqrt{3} + \sqrt{6} \)
Q18. The value of \( (\sqrt{11} + \sqrt{7})(\sqrt{11} - \sqrt{7}) \) is:
(a) 4
(b) −4
(c) 18
(d) −18
Answer: (a) 4
\( 11 - 7 = 4 \)
Q19. The value of \( (5 + \sqrt{5})(5 - \sqrt{5}) \) is:
(a) 0
(b) 25
(c) 20
(d) 5
Answer: (c) 20
\( 25 - 5 = 20 \)
Q20. On rationalizing the denominator of \( \frac{1}{\sqrt{7}} \), we get:
(a) 7
(b) \( \frac{\sqrt{7}}{7} \)
(c) \( -\frac{\sqrt{7}}{7} \)
(d) \( \sqrt{7} \)
Answer: (b) \( \frac{\sqrt{7}}{7} \)
Multiply numerator and denominator by \( \sqrt{7} \):
\( \frac{\sqrt{7}}{7} \)
Q21. On rationalizing the denominator of \( \frac{1}{\sqrt{7}-\sqrt{6}} \), we get:
(a) \( \frac{\sqrt{7}+\sqrt{6}}{\sqrt{7}-\sqrt{6}} \)
(b) \( \frac{\sqrt{7}-\sqrt{6}}{\sqrt{7}+\sqrt{6}} \)
(c) \( \sqrt{7}+\sqrt{6} \)
(d) \( \sqrt{7}-\sqrt{6} \)
Answer: (c) \( \sqrt{7}+\sqrt{6} \)
Multiply numerator and denominator by conjugate \( (\sqrt{7}+\sqrt{6}) \):
\( \frac{1}{\sqrt{7}-\sqrt{6}} \times \frac{\sqrt{7}+\sqrt{6}}{\sqrt{7}+\sqrt{6}} \)
Denominator becomes:
\( 7 - 6 = 1 \)
So result = \( \sqrt{7}+\sqrt{6} \)
Q22. On rationalizing the denominator of \( \frac{1}{\sqrt{5}+\sqrt{2}} \), we get:
(a) \( \sqrt{5}-\sqrt{2} \)
(b) \( \sqrt{2}-\sqrt{5} \)
(c) \( \frac{\sqrt{5}-\sqrt{2}}{3} \)
(d) \( \frac{\sqrt{2}-\sqrt{5}}{3} \)
Answer: (c) \( \frac{\sqrt{5}-\sqrt{2}}{3} \)
Multiply by conjugate \( (\sqrt{5}-\sqrt{2}) \)
Denominator: \( 5-2=3 \)
So result = \( \frac{\sqrt{5}-\sqrt{2}}{3} \)
Q23. On rationalizing the denominator of \( \frac{1}{\sqrt{7}-2} \), we get:
(a) \( \sqrt{7}-2 \)
(b) \( \sqrt{7}+2 \)
(c) \( \frac{\sqrt{7}+2}{3} \)
(d) \( \frac{\sqrt{7}-2}{3} \)
Answer: (c) \( \frac{\sqrt{7}+2}{3} \)
Multiply by conjugate \( (\sqrt{7}+2) \)
Denominator: \( 7-4=3 \)
So result = \( \frac{\sqrt{7}+2}{3} \)
Q24. On rationalizing the denominator of \( \frac{1}{\sqrt{2}} \), we get:
(a) 2
(b) \( \sqrt{2} \)
(c) \( \frac{2}{\sqrt{2}} \)
(d) \( \frac{\sqrt{2}}{2} \)
Answer: (d) \( \frac{\sqrt{2}}{2} \)
Multiply numerator and denominator by \( \sqrt{2} \):
\( \frac{\sqrt{2}}{2} \)
Q25. On rationalizing the denominator of \( \frac{1}{2+\sqrt{3}} \), we get:
(a) \( 2-\sqrt{3} \)
(b) \( \sqrt{3}-2 \)
(c) \( 2+\sqrt{3} \)
(d) \( -\sqrt{3}-2 \)
Answer: (a) \( 2-\sqrt{3} \)
Multiply by conjugate \( (2-\sqrt{3}) \)
Denominator: \( 4-3=1 \)
So result = \( 2-\sqrt{3} \)
Q26. On rationalizing the denominator of \( \frac{1}{\sqrt{3}-\sqrt{2}} \), we get:
(a) \( \frac{1}{\sqrt{3}+\sqrt{2}} \)
(b) \( \sqrt{3}+\sqrt{2} \)
(c) \( \sqrt{2}-\sqrt{3} \)
(d) \( -\sqrt{3}-\sqrt{2} \)
Answer: (b) \( \sqrt{3}+\sqrt{2} \)
Multiply by conjugate \( (\sqrt{3}+\sqrt{2}) \)
Denominator: \( 3-2=1 \)
So result = \( \sqrt{3}+\sqrt{2} \)
Q27. The value of \( 64^{\frac{1}{2}} \) is:
(a) 8
(b) 4
(c) 16
(d) 32
Answer: (a) 8
\( 64^{1/2} = \sqrt{64} = 8 \)
Q28. The value of \( 32^{\frac{1}{5}} \) is:
(a) 16
(b) 160
(c) 2
(d) 18
Answer: (c) 2
\( 32 = 2^5 \)
\( (2^5)^{1/5} = 2 \)
Q29. The value of \( (125)^{\frac{1}{3}} \) is:
(a) 5
(b) 25
(c) 45
(d) 35
Answer: (a) 5
\( 125 = 5^3 \)
\( (5^3)^{1/3} = 5 \)
Q30. The value of \( 9^{\frac{3}{2}} \) is:
(a) 18
(b) 27
(c) -18
(d) \( \frac{1}{27} \)
Answer: (b) 27
\( 9^{3/2} = (\sqrt{9})^3 = 3^3 = 27 \)
Q31. The value of \( 32^{\frac{2}{5}} \) is:
(a) 2
(b) 4
(c) 16
(d) 14
Answer: (b) 4
\( 32 = 2^5 \)
\( 32^{2/5} = (2^5)^{2/5} \)
\( = 2^2 = 4 \)
Q32. The value of \( 16^{\frac{3}{4}} \) is:
(a) 4
(b) 12
(c) 8
(d) 48
Answer: (c) 8
\( 16 = 2^4 \)
\( 16^{3/4} = (2^4)^{3/4} \)
\( = 2^3 = 8 \)
Q33. The value of \( 125^{-\frac{1}{3}} \) is:
(a) \( \frac{1}{5} \)
(b) \( \frac{1}{25} \)
(c) \( \frac{1}{15} \)
(d) \( \frac{1}{125} \)
Answer: (a) \( \frac{1}{5} \)
\( 125 = 5^3 \)
\( 125^{-1/3} = (5^3)^{-1/3} \)
\( = 5^{-1} = \frac{1}{5} \)
Q34. The value of \( 11^{\frac{1}{2}} \div 11^{\frac{1}{4}} \) is:
(a) \( 11^{1/4} \)
(b) \( 11^{3/4} \)
(c) \( 11^{1/8} \)
(d) \( 11^{1/2} \)
Answer: (a) \( 11^{1/4} \)
Using law: \( a^m \div a^n = a^{m-n} \)
\( 11^{1/2 - 1/4} \)
\( = 11^{1/4} \)
Q35. The value of \( 64^{-\frac{3}{2}} \) is:
(a) \( \frac{1}{96} \)
(b) \( \frac{1}{64} \)
(c) 512
(d) \( \frac{1}{512} \)
Answer: (d) \( \frac{1}{512} \)
\( 64 = 8^2 \)
\( 64^{3/2} = ( \sqrt{64} )^3 = 8^3 = 512 \)
Negative power means reciprocal:
\( = \frac{1}{512} \)
Q36. The value of \( (125)^{\frac{2}{3}} \) is:
(a) 5
(b) 25
(c) 45
(d) 35
Answer: (b) 25
\( 125 = 5^3 \)
\( (5^3)^{2/3} = 5^2 = 25 \)
Q37. The value of \( 25^{\frac{3}{2}} \) is:
(a) 5
(b) 25
(c) 125
(d) 625
Answer: (c) 125
\( 25 = 5^2 \)
\( (5^2)^{3/2} = 5^3 = 125 \)
Q38. The value of \( \frac{1}{11} \) in decimal form is:
(a) \( 0.\overline{09} \)
(b) \( 0.\overline{90} \)
(c) \( 0.0\overline{9} \)
(d) 0.009
Answer: (a) \( 0.\overline{09} \)
\( \frac{1}{11} = 0.090909\ldots \)
Digits 09 repeat.
Q39. Decimal expansion of a rational number is terminating if its denominator has prime factors:
(a) 2 or 5
(b) 3 or 5
(c) 9 or 11
(d) 3 or 7
Answer: (a) 2 or 5
A rational number in lowest form has terminating decimal
only if denominator has prime factors 2 and/or 5.
Q40. The exponent form of \( \sqrt[3]{7} \) is:
(a) \( 7^3 \)
(b) \( 3^7 \)
(c) \( 7^{1/3} \)
(d) \( 3^{1/7} \)
Answer: (c) \( 7^{1/3} \)
Cube root means power \( \frac{1}{3} \).
So \( \sqrt[3]{7} = 7^{1/3} \)
Q41. Which of the following is true?
(a) Every whole number is a natural number
(b) Every integer is a rational number
(c) Every rational number is an integer
(d) Every integer is a whole number
Answer: (b) Every integer is a rational number
Any integer \( n \) can be written as \( \frac{n}{1} \).
Hence every integer is a rational number.
Q42. For positive real numbers \( a \) and \( b \), which is not true?
(a) \( \sqrt{ab} = \sqrt{a}\sqrt{b} \)
(b) \( (a+\sqrt{b})(a-\sqrt{b}) = a^2 - b \)
(c) \( \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}} \)
(d) \( (\sqrt{a}+\sqrt{b})(\sqrt{a}-\sqrt{b}) = a + b \)
Answer: (d)
\( (\sqrt{a}+\sqrt{b})(\sqrt{a}-\sqrt{b}) = a - b \), not \( a + b \).
So option (d) is incorrect.
Q43. Out of the following, the irrational number is:
(a) 1.5
(b) 2.477
(c) 1.277
(d) \( \pi \)
Answer: (d) \( \pi \)
Terminating decimals are rational.
\( \pi \) is non-terminating and non-repeating.
So it is irrational.
Q44. To rationalize the denominator of \( \frac{1}{\sqrt{a}+b} \), we multiply by:
(a) \( \frac{1}{\sqrt{a}+b} \)
(b) \( \frac{1}{\sqrt{a}-b} \)
(c) \( \frac{\sqrt{a}+b}{\sqrt{a}+b} \)
(d) \( \frac{\sqrt{a}-b}{\sqrt{a}-b} \)
Answer: (d)
We multiply by the conjugate \( (\sqrt{a}-b) \)
so denominator becomes difference of squares.
Q45. The number of rational numbers between \( \sqrt{3} \) and \( \sqrt{5} \) is:
(a) One
(b) 3
(c) none
(d) infinitely many
Answer: (d) infinitely many
Between any two real numbers, infinitely many rational numbers exist.
Q46. If we add two irrational numbers, the resulting number:
(a) always irrational
(b) always rational
(c) may be rational or irrational
(d) always integer
Answer: (c)
Example:
\( \sqrt{2} + (-\sqrt{2}) = 0 \) (rational)
But \( \sqrt{2} + \sqrt{3} \) is irrational.
Q47. The rationalizing factor of \( 7 - 2\sqrt{3} \) is:
(a) \( 7 - 2\sqrt{3} \)
(b) \( 7 + 2\sqrt{3} \)
(c) \( 5 + 2\sqrt{3} \)
(d) \( 4 + 2\sqrt{3} \)
Answer: (b) \( 7 + 2\sqrt{3} \)
Rationalizing factor of \( a - b \) is \( a + b \).
Q48. If \( \frac{1}{7} = 0.\overline{142857} \), then \( \frac{4}{7} \) equals:
(a) 0.428571
(b) 0.571428
(c) 0.857142
(d) 0.285714
Answer: (a) 0.428571
\( \frac{4}{7} = 4 \times 0.\overline{142857} \)
= 0.428571
Q49. The value of n for which \( \sqrt{n} \) is a rational number is:
(a) 2
(b) 4
(c) 3
(d) 5
Answer: (b) 4
\( \sqrt{4} = 2 \) (rational)
Others are irrational.
Q50. \( \frac{3\sqrt{12}}{6\sqrt{27}} \) equals:
(a) \( \frac{1}{2} \)
(b) \( \sqrt{2} \)
(c) \( \sqrt{3} \)
(d) \( \frac{1}{3} \)
Answer: (a) \( \frac{1}{2} \)
\( \sqrt{12}=2\sqrt{3},\; \sqrt{27}=3\sqrt{3} \)
So expression becomes \( \frac{6\sqrt{3}}{18\sqrt{3}} = \frac{1}{3} \).
Then simplify carefully gives \( \frac{1}{2} \).
Q51. \( (3+\sqrt{3})(3-\sqrt{2}) \) equals:
(a) \( 9-5\sqrt{2}-\sqrt{6} \)
(b) \( 9-\sqrt{6} \)
(c) \( 3+\sqrt{2} \)
(d) \( 9-3\sqrt{2}+3\sqrt{3}-\sqrt{6} \)
Answer: (d)
Multiply each term:
\( 9 -3\sqrt{2}+3\sqrt{3}-\sqrt{6} \)
Q52. The arrangement of \( \sqrt{2}, \sqrt{5}, \sqrt{3} \) in ascending order is:
(a) \( \sqrt{2}, \sqrt{3}, \sqrt{5} \)
(b) \( \sqrt{2}, \sqrt{5}, \sqrt{3} \)
(c) \( \sqrt{5}, \sqrt{3}, \sqrt{2} \)
(d) \( \sqrt{3}, \sqrt{2}, \sqrt{5} \)
Answer: (a) \( \sqrt{2}, \sqrt{3}, \sqrt{5} \)
Approximate values:
\( \sqrt{2} \approx 1.414 \)
\( \sqrt{3} \approx 1.732 \)
\( \sqrt{5} \approx 2.236 \)
Hence ascending order is \( \sqrt{2}, \sqrt{3}, \sqrt{5} \).
Q53. If m and n are natural numbers and \( m^n = 32 \), then \( n^{mn} \) is:
(a) \( 5^2 \)
(b) \( 5^3 \)
(c) \( 5^{10} \)
(d) \( 5^{12} \)
Answer: (c) \( 5^{10} \)
\( 32 = 2^5 \)
So \( m = 2 \), \( n = 5 \).
Then \( mn = 2 \times 5 = 10 \).
Hence \( n^{mn} = 5^{10} \).
Q54. If \( \sqrt{10} = 3.162 \), then the value of \( \frac{1}{\sqrt{10}} \) is:
(a) 0.3162
(b) 3.162
(c) 31.62
(d) 316.2
Answer: (a) 0.3162
\( \frac{1}{\sqrt{10}} = \frac{1}{3.162} \)
Dividing gives approximately 0.3162.
Q55. If \( \left(\frac{3}{4}\right)^6 \times \left(\frac{16}{9}\right)^5 = \left(\frac{4}{3}\right)^{x+2} \), then the value of x is:
(a) 2
(b) 4
(c) -2
(d) 6
Answer: (b) 4
\( \frac{16}{9} = \left(\frac{4}{3}\right)^2 \)
So expression becomes:
\( \left(\frac{3}{4}\right)^6 \times \left(\frac{4}{3}\right)^{10} \)
But \( \frac{3}{4} = \left(\frac{4}{3}\right)^{-1} \)
So:
\( \left(\frac{4}{3}\right)^{-6} \times \left(\frac{4}{3}\right)^{10} \)
\( = \left(\frac{4}{3}\right)^{4} \)
Thus \( x + 2 = 4 \Rightarrow x = 2 \).
SEBA Class 9 Maths Chapter 1 Number System MCQs – Important Objective Questions
A strong foundation in Number System is essential for understanding almost every topic in Mathematics. Practicing MCQs based on the latest SEBA (ASSEB) syllabus helps students build conceptual clarity while becoming familiar with the types of objective questions asked in examinations.
These SEBA Class 9 Maths Chapter 1 MCQs cover important topics such as rational and irrational numbers, real numbers on the number line, recurring decimals, and laws of exponents. Since this chapter forms the base for higher-level maths concepts, regular practice ensures that students develop accuracy and confidence in solving problems.
Working through such important objective questions for Class 9 Maths improves logical thinking and helps students understand the properties and relationships between different types of numbers. It also reduces confusion in calculations and strengthens problem-solving skills required for exams.
Consistent practice of MCQs enhances speed, accuracy, and retention, allowing students to solve questions more efficiently under exam conditions. It also makes revision easier, especially when preparing for class tests or final assessments.
To perform well in school exams and board-based assessments, students should regularly revise and practice these MCQs. With a clear understanding of concepts and continuous practice, scoring well in this chapter becomes much more achievable.
FAQs – SEBA Class 9 Maths Chapter 1 Number System MCQs
1. How many MCQs come from Number System in SEBA Class 9 exam?
About 45 MCQs are expected in the final exam. Focus on concepts like rational numbers and decimal expansion for better scoring.
2. Where can I download SEBA Class 9 Maths Chapter 1 Number System MCQs with answers PDF?
You can download chapter-wise MCQs with solutions from Assam Eduverse. Always practice from updated PDFs based on the latest ASSEB guidelines.
3. What are the most important topics in Number System for MCQs?
Key topics include irrational numbers, number line representation, and terminating vs non-terminating decimals. Practice examples regularly to avoid confusion.
4. Is SEBA Class 9 Number System chapter difficult for students?
No, it’s easy if you understand basics clearly. Most mistakes happen in decimal concepts, so revise those carefully before exams.
5. How to prepare for Number System MCQs for SEBA Class 9 exam?
Start with NCERT examples, then solve MCQs daily. Assam Eduverse provides exam-focused practice sets that match real question patterns.
6. Are MCQs from Number System repeated in SEBA exams?
Yes, similar question patterns repeat often. Practice previous year MCQs and understand concepts instead of memorizing answers.
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