SEBA Class 9 Science Chapter 8 Motion MCQs (2026–27) – Assam Eduverse
Master the fundamentals of kinematics with SEBA Class 9 Science Chapter 8 Motion MCQs (2026–27), designed as per the latest ASSEB syllabus and updated board exam pattern. These SEBA Class 9 Science Chapter 8 Motion MCQs include important objective questions, numerical-based MCQs, and concept-oriented practice sets to support effective exam preparation.
Prepared by Assam Eduverse subject experts, these SEBA Class 9 Science Chapter 8 MCQs cover essential topics such as distance and displacement, speed and velocity, uniform and non-uniform motion, acceleration, graphs of motion, equations of motion, and circular motion. Practicing these Motion MCQs Class 9 SEBA and Assam Board Class 9 Science objective questions helps improve conceptual understanding and numerical accuracy. You can also explore more practice from Class 9 Science chapterwise MCQs and SEBA Class 9 MCQs.
Regular practice of these ASSEB Class 9 Science Important MCQs will strengthen your preparation and boost exam performance. For detailed explanations, visit SEBA Class 9 Science Chapter 8 Motion Solutions, or explore additional resources like SEBA Class 9 & 10 study materials and SEBA Class 9 syllabus.
SEBA Class 9 Science Chapter 8 Motion MCQs – ASSEB 2026–27 Board Exam Practice
Table of Contents
Before You Start
Test your knowledge with the SEBA Class 9 Science MCQs Quiz. Read each question carefully and select the correct answer. Your answer is checked instantly after you choose an option, and a detailed explanation appears immediately to help you learn every concept and improve your exam preparation.
In physics, the macroscopic motion of an object is most accurately described as a:
✅ Correct Answer
Concept Explanation
An object is said to be in motion if its position coordinates shift continuously over a period of time relative to a stationary observer or surroundings. Changes in shape, size, or mass fall into mechanical deformation or chemistry rather than kinematics.
To describe and specify the precise spatial position of a moving object, we fundamentally require:
✅ Correct Answer
Concept Explanation
Position is a relative measurement. To declare how far away or in what direction an object is located, we must choose a fixed anchoring location known as a reference point or origin (for example, stating "the library is 2 kilometres north from the railway station," where the station serves as our reference).
The total, cumulative path length covered by a body during its entire journey is defined as:
✅ Correct Answer
Concept Explanation
Distance is a scalar quantity that tracks the complete actual path traveled by an object, regardless of the direction it took. It can never be negative or decrease during a journey.
The vector quantity that tracks the shortest straight-line distance measured from the initial position to the final position of an object is:
✅ Correct Answer
Concept Explanation
Displacement is a vector parameter representing an object's net change in position. It cares only about the starting and ending benchmarks, forming a straight vector arrow connecting them, regardless of the twists and turns taken in between.
The total displacement of a moving body drops down to a value of exactly zero whenever:
✅ Correct Answer
Concept Explanation
Because displacement measures the straight-line distance between the start and end points, if an object travels along a path (such as a circular track or a round-trip lap) and returns to its exact starting point, its net positional change is zero, making its displacement zero even if it traveled a large distance.
When a body covers perfectly equal distances within completely equal consecutive intervals of time, its motion is classified as:
✅ Correct Answer
Concept Explanation
An object is in uniform motion when its speed remains constant without fluctuations. Even if the time chunks are extremely small, covering identical distance intervals proves that the object is traveling at a steady rate without speeding up or slowing down.
The standard derived SI unit utilized internationally to measure the magnitude of speed is:
✅ Correct Answer
Concept Explanation
While km/h is a common metric unit for vehicular speeds, the base SI unit for length is the metre and for time is the second. Therefore, the standard scientific base unit used to measure speed is metres per second (m/s).
By mechanical definition, the rate of distance covered per unit time is called:
✅ Correct Answer
Concept Explanation
Speed is the scalar rate tracking how fast an object covers distance ($\text{Speed} = \text{Distance} / \text{Time}$). It does not contain any directional data, specifying only the rate of motion.
Kinematically, how does vector velocity differ from simple scalar speed?
✅ Correct Answer
Concept Explanation
Velocity is a vector parameter defined as displacement per unit time. It can be thought of as speed with a directional heading (such as traveling 60 km/h due West). Velocity shifts if either the object changes its speed or changes its direction.
The average speed parameter of a non-uniform journey is computed standardly by dividing the:
✅ Correct Answer
Concept Explanation
Because real-world journeys involve changing speeds, we calculate an overarching single metric called average speed ($\text{Total Distance} / \text{Total Time}$). This provides a single scalar baseline representing the uniform rate required to complete the identical trip in that time frame.
The physical parameter defined as the rate of change of velocity per unit time is:
✅ Correct Answer
Concept Explanation
Acceleration ($a$) is a vector quantity that measures how rapidly an object's velocity is changing ($\text{Acceleration} = \Delta v / \Delta t$). An object accelerates if it speeds up, slows down, or changes its direction of travel.
The standard derived SI unit utilized internationally to express the value of acceleration is:
✅ Correct Answer
Concept Explanation
Because acceleration is change in velocity (measured in m/s) divided by an interval of time (measured in seconds), its derived unit compounds time twice: $\text{(m/s)} / \text{s} =$ m/s² (metres per second squared).
When the velocity vector of a moving vehicle decreases uniformly over time, its acceleration value is:
✅ Correct Answer
Concept Explanation
If a moving body slows down (such as a car braking to a halt), its final velocity is lower than its initial velocity ($v < u$). Calculating $\Delta v = v - u$ yields a negative value, meaning the acceleration is negative, a phenomenon termed retardation or deceleration.
When plotted on a graph, the distance-time relationship for an object traveling in perfect uniform motion forms a:
✅ Correct Answer
Concept Explanation
Because uniform motion implies that distance increases in direct proportion to time, a distance-time graph yields a linear relationship. This plots as a straight line inclined at an angle to the horizontal time axis. A curved line indicates non-uniform, accelerated motion.
The mathematical slope derived from a distance-time graphical plot directly represents the object's:
✅ Correct Answer
Concept Explanation
On a distance-time graph, the slope calculation corresponds to the change in distance ($\Delta s$) divided by the change in time ($\Delta t$). Since $\Delta s / \Delta t$ is the formula for speed, a steeper slope indicates a faster moving object.
Calculating the absolute geometric area enclosed beneath a velocity-time graph reveals the object's:
✅ Correct Answer
Concept Explanation
Integrating or finding the mathematical area beneath a velocity-time plot line over a given interval yields the product of velocity and time. This product resolves directly to displacement (or total distance, provided the path line does not cross below the zero-velocity axis into negative values).
If an object's velocity-time graph is a straight line running perfectly parallel to the horizontal time axis, the object is moving under:
✅ Correct Answer
Concept Explanation
A horizontal line on a velocity-time graph indicates that the velocity value is unchanged as time passes. Because acceleration is the change in velocity over time ($\Delta v / \Delta t$), a constant velocity profile means $\Delta v = 0$, resulting in zero acceleration.
The classic kinematic formula $v = u + at$ describes the mathematical relationship operating between:
✅ Correct Answer
Concept Explanation
The first equation of motion ($v = u + at$) explicitly relates final velocity ($v$) and initial velocity ($u$) to elapsed time ($t$) under a state of constant acceleration ($a$). This is known as the velocity-time relation.
An object tracking a circular pathway at a perfectly uniform, unfluctuating speed possesses:
✅ Correct Answer
Concept Explanation
An object in uniform circular motion is constantly accelerating because its direction of travel changes at every single point along the loop, shifting its velocity vector. Since acceleration depends on changes to the velocity vector, a change in direction creates acceleration even if speed is constant.
The explicit mechanical name given to motion along a circular tracking path at a completely constant speed is:
✅ Correct Answer
Concept Explanation
When an object travels along a circular path with a constant speed, its motion is called uniform circular motion. It is a classic example of an accelerated motion because the direction of velocity changes continuously over time.
Assertion (A): In perfect uniform linear motion, the net acceleration of an object is always exactly equal to zero.
Reason (R): By definition, the directional velocity of an object remains completely constant throughout uniform linear motion.
✅ Correct Answer
Concept Explanation
Uniform linear motion means an object covers equal distances in equal intervals of time along a straight path, meaning its velocity does not speed up, slow down, or shift direction. Since acceleration is mathematically defined as the rate of change of velocity ($\Delta v / \Delta t$), a constant velocity ensures that acceleration remains at zero.
Assertion (A): Both instantaneous speed and directional velocity share the exact same standard units of measurement.
Reason (R): In the International System of Units (SI), both speed and velocity are quantified using metres per second (m/s).
✅ Correct Answer
Concept Explanation
Although speed is a scalar (magnitude only) and velocity is a vector (magnitude plus direction), they both quantify the rate of motion per unit time. Because the standard units for distance/displacement is the metre and for time is the second, their SI derived unit is identically m/s, making the reason a perfect explanation.
Assertion (A): The physical slope calculated from a linear velocity-time graph represents the acceleration of the moving body.
Reason (R): Physical acceleration is defined as the rate of change of velocity per unit time.
✅ Correct Answer
Concept Explanation
On a velocity-time graph, the vertical axis plots velocity ($\Delta v$) and the horizontal axis tracks time ($\Delta t$). Calculating the slope equals the rise over run ($\Delta v / \Delta t$). Because this ratio matches the exact mathematical definition of acceleration, the reason directly validates the assertion.
Assertion (A): The net distance covered by a moving object during its journey can never hold a value of zero.
Reason (R): The total displacement of an object can drop to zero if it completes its path loop and returns to its initial starting point.
✅ Correct Answer
Concept Explanation
The assertion statement is false because the distance traveled by an object can be zero, provided the object remains completely at rest without moving. If it moves at all, distance must increase positively. The reason statement is completely true: displacement drops to zero whenever the final position matches the starting origin.
Assertion (A): An object moving at a perfectly constant speed along a circular track is classified as undergoing accelerated motion.
Reason (R): Kinematical acceleration depends strictly and exclusively upon changes in the scalar speed of the object.
✅ Correct Answer
Concept Explanation
The assertion is true: an object in uniform circular motion is constantly accelerating because its direction of travel changes at every single point along the loop, shifting its velocity vector. The reason statement is false because acceleration depends on changes to the velocity vector, which can be caused by a change in speed, a change in direction, or both.
In physics, the macroscopic motion of an object is most accurately described as a:
✅ Correct Answer
Concept Explanation
An object is said to be in motion if its position coordinates shift continuously over a period of time relative to a stationary observer or surroundings. Changes in shape, size, or mass fall into mechanical deformation or chemistry rather than kinematics.
To describe and specify the precise spatial position of a moving object, we fundamentally require:
✅ Correct Answer
Concept Explanation
Position is a relative measurement. To declare how far away or in what direction an object is located, we must choose a fixed anchoring location known as a reference point or origin (for example, stating "the library is 2 kilometres north from the railway station," where the station serves as our reference).
The total, cumulative path length covered by a body during its entire journey is defined as:
✅ Correct Answer
Concept Explanation
Distance is a scalar quantity that tracks the complete actual path traveled by an object, regardless of the direction it took. It can never be negative or decrease during a journey.
The vector quantity that tracks the shortest straight-line distance measured from the initial position to the final position of an object is:
✅ Correct Answer
Concept Explanation
Displacement is a vector parameter representing an object's net change in position. It cares only about the starting and ending benchmarks, forming a straight vector arrow connecting them, regardless of the twists and turns taken in between.
The total displacement of a moving body drops down to a value of exactly zero whenever:
✅ Correct Answer
Concept Explanation
Because displacement measures the straight-line distance between the start and end points, if an object travels along a path (such as a circular track or a round-trip lap) and returns to its exact starting point, its net positional change is zero, making its displacement zero even if it traveled a large distance.
When a body covers perfectly equal distances within completely equal consecutive intervals of time, its motion is classified as:
✅ Correct Answer
Concept Explanation
An object is in uniform motion when its speed remains constant without fluctuations. Even if the time chunks are extremely small, covering identical distance intervals proves that the object is traveling at a steady rate without speeding up or slowing down.
The standard derived SI unit utilized internationally to measure the magnitude of speed is:
✅ Correct Answer
Concept Explanation
While km/h is a common metric unit for vehicular speeds, the base SI unit for length is the metre and for time is the second. Therefore, the standard scientific base unit used to measure speed is metres per second (m/s).
By mechanical definition, the rate of distance covered per unit time is called:
✅ Correct Answer
Concept Explanation
Speed is the scalar rate tracking how fast an object covers distance ($\text{Speed} = \text{Distance} / \text{Time}$). It does not contain any directional data, specifying only the rate of motion.
Kinematically, how does vector velocity differ from simple scalar speed?
✅ Correct Answer
Concept Explanation
Velocity is a vector parameter defined as displacement per unit time. It can be thought of as speed with a directional heading (such as traveling 60 km/h due West). Velocity shifts if either the object changes its speed or changes its direction.
The average speed parameter of a non-uniform journey is computed standardly by dividing the:
✅ Correct Answer
Concept Explanation
Because real-world journeys involve changing speeds, we calculate an overarching single metric called average speed ($\text{Total Distance} / \text{Total Time}$). This provides a single scalar baseline representing the uniform rate required to complete the identical trip in that time frame.
The physical parameter defined as the rate of change of velocity per unit time is:
✅ Correct Answer
Concept Explanation
Acceleration ($a$) is a vector quantity that measures how rapidly an object's velocity is changing ($\text{Acceleration} = \Delta v / \Delta t$). An object accelerates if it speeds up, slows down, or changes its direction of travel.
The standard derived SI unit utilized internationally to express the value of acceleration is:
✅ Correct Answer
Concept Explanation
Because acceleration is change in velocity (measured in m/s) divided by an interval of time (measured in seconds), its derived unit compounds time twice: $\text{(m/s)} / \text{s} =$ m/s² (metres per second squared).
When the velocity vector of a moving vehicle decreases uniformly over time, its acceleration value is:
✅ Correct Answer
Concept Explanation
If a moving body slows down (such as a car braking to a halt), its final velocity is lower than its initial velocity ($v < u$). Calculating $\Delta v = v - u$ yields a negative value, meaning the acceleration is negative, a phenomenon termed retardation or deceleration.
When plotted on a graph, the distance-time relationship for an object traveling in perfect uniform motion forms a:
✅ Correct Answer
Concept Explanation
Because uniform motion implies that distance increases in direct proportion to time, a distance-time graph yields a linear relationship. This plots as a straight line inclined at an angle to the horizontal time axis. A curved line indicates non-uniform, accelerated motion.
The mathematical slope derived from a distance-time graphical plot directly represents the object's:
✅ Correct Answer
Concept Explanation
On a distance-time graph, the slope calculation corresponds to the change in distance ($\Delta s$) divided by the change in time ($\Delta t$). Since $\Delta s / \Delta t$ is the formula for speed, a steeper slope indicates a faster moving object.
Calculating the absolute geometric area enclosed beneath a velocity-time graph reveals the object's:
✅ Correct Answer
Concept Explanation
Integrating or finding the mathematical area beneath a velocity-time plot line over a given interval yields the product of velocity and time. This product resolves directly to displacement (or total distance, provided the path line does not cross below the zero-velocity axis into negative values).
If an object's velocity-time graph is a straight line running perfectly parallel to the horizontal time axis, the object is moving under:
✅ Correct Answer
Concept Explanation
A horizontal line on a velocity-time graph indicates that the velocity value is unchanged as time passes. Because acceleration is the change in velocity over time ($\Delta v / \Delta t$), a constant velocity profile means $\Delta v = 0$, resulting in zero acceleration.
The classic kinematic formula $v = u + at$ describes the mathematical relationship operating between:
✅ Correct Answer
Concept Explanation
The first equation of motion ($v = u + at$) explicitly relates final velocity ($v$) and initial velocity ($u$) to elapsed time ($t$) under a state of constant acceleration ($a$). This is known as the velocity-time relation.
An object tracking a circular pathway at a perfectly uniform, unfluctuating speed possesses:
✅ Correct Answer
Concept Explanation
An object in uniform circular motion is constantly accelerating because its direction of travel changes at every single point along the loop, shifting its velocity vector. Since acceleration depends on changes to the velocity vector, a change in direction creates acceleration even if speed is constant.
The explicit mechanical name given to motion along a circular tracking path at a completely constant speed is:
✅ Correct Answer
Concept Explanation
When an object travels along a circular path with a constant speed, its motion is called uniform circular motion. It is a classic example of an accelerated motion because the direction of velocity changes continuously over time.
Assertion (A): In perfect uniform linear motion, the net acceleration of an object is always exactly equal to zero.
Reason (R): By definition, the directional velocity of an object remains completely constant throughout uniform linear motion.
✅ Correct Answer
Concept Explanation
Uniform linear motion means an object covers equal distances in equal intervals of time along a straight path, meaning its velocity does not speed up, slow down, or shift direction. Since acceleration is mathematically defined as the rate of change of velocity ($\Delta v / \Delta t$), a constant velocity ensures that acceleration remains at zero.
Assertion (A): Both instantaneous speed and directional velocity share the exact same standard units of measurement.
Reason (R): In the International System of Units (SI), both speed and velocity are quantified using metres per second (m/s).
✅ Correct Answer
Concept Explanation
Although speed is a scalar (magnitude only) and velocity is a vector (magnitude plus direction), they both quantify the rate of motion per unit time. Because the standard units for distance/displacement is the metre and for time is the second, their SI derived unit is identically m/s, making the reason a perfect explanation.
Assertion (A): The physical slope calculated from a linear velocity-time graph represents the acceleration of the moving body.
Reason (R): Physical acceleration is defined as the rate of change of velocity per unit time.
✅ Correct Answer
Concept Explanation
On a velocity-time graph, the vertical axis plots velocity ($\Delta v$) and the horizontal axis tracks time ($\Delta t$). Calculating the slope equals the rise over run ($\Delta v / \Delta t$). Because this ratio matches the exact mathematical definition of acceleration, the reason directly validates the assertion.
Assertion (A): The net distance covered by a moving object during its journey can never hold a value of zero.
Reason (R): The total displacement of an object can drop to zero if it completes its path loop and returns to its initial starting point.
✅ Correct Answer
Concept Explanation
The assertion statement is false because the distance traveled by an object can be zero, provided the object remains completely at rest without moving. If it moves at all, distance must increase positively. The reason statement is completely true: displacement drops to zero whenever the final position matches the starting origin.
Assertion (A): An object moving at a perfectly constant speed along a circular track is classified as undergoing accelerated motion.
Reason (R): Kinematical acceleration depends strictly and exclusively upon changes in the scalar speed of the object.
✅ Correct Answer
Concept Explanation
The assertion is true: an object in uniform circular motion is constantly accelerating because its direction of travel changes at every single point along the loop, shifting its velocity vector. The reason statement is false because acceleration depends on changes to the velocity vector, which can be caused by a change in speed, a change in direction, or both.
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SEBA Class 9 Science Chapter 8 Motion MCQs – Important Objective Questions
A strong understanding of Motion is essential for building a solid foundation in Physics. Practicing well-structured MCQs based on the latest SEBA (ASSEB) syllabus helps students develop clarity in both conceptual and numerical aspects of the chapter while becoming familiar with exam-oriented question patterns.
These SEBA Class 9 Science Chapter 8 MCQs cover key topics such as speed, velocity, acceleration, equations of motion, and graphical representation through distance-time and velocity-time graphs. Since this chapter involves both theory and calculations, regular practice is important for improving problem-solving skills and understanding real-life applications of motion.
By solving these important objective questions for Class 9 Science, students can strengthen their ability to interpret graphs, apply formulas correctly, and solve numerical problems with confidence. It also helps in avoiding common mistakes related to units, formulas, and conceptual differences between physical quantities.
Consistent MCQ practice enhances accuracy, speed, and confidence. Students become more comfortable with different types of numerical and conceptual questions, manage time effectively, and can revise the entire chapter quickly before exams.
To perform well in school tests and board-level examinations, students should include these MCQs in their regular study routine. With continuous practice and a clear understanding of concepts, scoring high in this chapter becomes much easier and more achievable.
FAQs – SEBA Class 9 Science Chapter 8 Motion MCQs
1. How many MCQs come from Motion chapter in SEBA Class 9 exam?
About 3-4 MCQs are expected as per latest ASSEB guidelines. Focus on formulas and graphs—they are frequently asked in exams.
2. Which topics are most important for Motion MCQs in SEBA Class 9?
Velocity, acceleration, distance-time graphs, and equations of motion are key. Practice numericals—they often appear as MCQs.
3. Where can I download SEBA Class 9 Motion MCQs with answers PDF?
You can find chapter-wise MCQs on Assam Eduverse and similar sites. Always revise from solved PDFs for quick exam practice.
4. Are numericals asked as MCQs in Class 9 Motion chapter?
Yes, simple numericals based on equations of motion are common. Learn formulas and practice quick calculations to save time.
5. Is Chapter 8 Motion difficult for SEBA Class 9 students?
No, it’s easy if concepts are clear. Start with basics, then solve MCQs daily—Assam Eduverse practice sets help a lot.
6. How to prepare SEBA Class 9 Science Chapter 8 Motion MCQs quickly?
Revise formulas, practice previous MCQs, and focus on graphs. Short daily practice sessions improve accuracy before exams.
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